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Vsevolod [243]
3 years ago
15

What are the measures of angle a,b,c? show your work and explain

Mathematics
1 answer:
maks197457 [2]3 years ago
8 0

Answer: A= 40. Vertical angles are congruent; B=50. 40+90=130 180-130=50; c=115 bc 180-65=115

Step-by-step explanation:

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What is the volume, in cubic M, of a cylinder with a height of 13M and a base radius of 3M, to the nearest 10th Place?
irina [24]

Answer:

The volume of the cylinder is 367.6 M^3

Step-by-step explanation:

Mathematically, we have the volume of a cylinder calculated as follows;

V = pi * r^2 * h

r is the base radius given as 3 m

h is the height given as 13 m

So, we have the volume as;

V = 22/7 * 3^2 * 13 = 367.6 M^3

7 0
3 years ago
Read 2 more answers
Verify cot x sec^4x=cotx +2tanx +tan^3x
Tanzania [10]

Answer:

See explanation

Step-by-step explanation:

We want to verify that:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

Verifying from left, we have

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { \tan}^{2} x )^{2}

Expand the perfect square in the right:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \: ( 1 +  { 2\tan}^{2} x  + { \tan}^{4} x)

We expand to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  \cot(x){ 2\tan}^{2} x  +\cot(x) { \tan}^{4} x

We simplify to get:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{2} x}{{ \cos}^{2} x}   +\frac{ \cos(x) }{\sin(x) ) }  \times  \frac{{ \sin}^{4} x}{{ \cos}^{4} x}

Cancel common factors:

\cot(x)  \:  { \sec}^{4} x  = \cot(x)  \:   +  2 \frac{{ \sin}x}{{ \cos}x}   +\frac{{ \sin}^{3} x}{{ \cos}^{3} x}

This finally gives:

\cot(x)  \:  { \sec}^{4} x =  \cot(x) + 2 \tan(x)   +  { \tan}^{3} x

3 0
3 years ago
What’s the answer to number 1?
Darya [45]

Answer:

increase = New number - original number

inc % = (increase ÷ original number) *100%

Step-by-step explanation:

133 - 76 = 56

inc % = 57 ÷ 76 = 0.75

0.75*100% = 75%

7 0
2 years ago
Solve -1 < x + 1 ≤ 6
andrey2020 [161]

Answer:

-2<x≤5

Step-by-step :

-1<x+1≤6 So fisrt what every we do to one side we must do to the other. In this case it's a bit different since we are dealing with inequalities.

-1<x+1≤6 I would start off by isolating x in the middle.

-1<x+1≤6 I subtracted 1 from all three sides.

-1     -1   -1

Now your equation should look like this:

-2<x≤5  Now there is really nothing much we can do here since we were just trying to get x by its self.

Answer : -2<x≤5

7 0
2 years ago
Nathan is playing golf at a golf course. The height of the golf ball from the ground, in feet, x seconds after the ball is hit i
lozanna [386]

Answer:

A.  the times at which the golf ball is on the ground

Step-by-step explanation:

The expression of the function is

h(x)= -4x^2+36x

The roots can be seen in the image below

You have a formula which represents the height over time.

The roots of the equation indicate that the height is equal to zero

The correct option is

A.  the times at which the golf ball is on the ground

The ball is in the ground at x= 0 and x = 9 seconds

8 0
3 years ago
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