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2 years ago

(-4-3)(1-(3+5))x5= how do you solve that problem ?

Mathematics

1 answer:

zavuch27 [327]2 years ago

7 0

(-4 - 3)(1 - (3 + 5)) × 5
(-7)(-1 - 2) × 5
(-7)(-3) × 5
21 × 5
105

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What number has the absolute value of 16

german

The Answer is -16

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2 years ago

Esme plans to flip a fair coin 3 times and record the results of each flip.

MariettaO [177]

Answer:

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2 years ago

Forces of 9 lbs and 13 lbs act at a 38º angle to each other. Find the magnitude of the resultant force and the angle that the re

fiasKO [112]

Answer: $R=20.84\ lb\quad 22.57^{\circ},15.43^{\circ}$

Step-by-step explanation:

Given

Two forces of 9 and 13 lbs acts $38^{\circ}$ angle to each other

The resultant of the two forces is given by

$\Rightarrow R=\sqrt{a^2+b^2+2ab\cos \theta}$

Insert the values

$\Rightarrow R=\sqrt{9^2+13^2+2(9)(13)\cos 38^{\circ}}\\\Rightarrow R=\sqrt{81+169+184.394}\\\Rightarrow R=\sqrt{434.394}\\\Rightarrow R=20.84\ lb$

Resultant makes an angle of

$\Rightarrow \alpha=\tan^{-1}\left( \dfrac{b\sin \theta}{a+b\cos \theta}\right)\\\\\text{Considering 9 lb force along the x-axis}\\\\\Rightarrow \alpha =\tan^{-1}\left( \dfrac{13\sin 38^{\circ}}{9+13\cos 38^{\circ}}\right)\\\\\Rightarrow \alpha =\tan^{-1}(\dfrac{8}{19.244})\\\\\Rightarrow \alpha=22.57^{\circ}$

So, the resultant makes an angle of $22.57^{\circ}$ with 9 lb force

Angle made with 13 lb force is $38^{\circ}-22.57^{\circ}=15.43^{\circ}$

7 0

2 years ago

Read 2 more answers

Gloria's pontoon boat holds 24 gallons of gas.

Darya [45]

Answer:

ok so if the girl added 13 gallons of gas 11 gallons were already there, if 14 gallons then 10 gallons were there, if 13,4 then 10,6 gallons were already there

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2 years ago

Go step by step to reduce the radical. V108 VOVO try You must answer all questions above in order to submit.

katen-ka-za [31]

To reduce the radical, you have to factorize 108.

108 is a multiple of 3, so to factorize it, you can divide it by 3