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scoundrel [369]
4 years ago
8

How long was a million days ago in hours ?

Mathematics
1 answer:
Komok [63]4 years ago
3 0
24000000. 1000000*24= 24000000, therefore, a million days ago in hours would be 24000000.
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Convert Repeating Decimal to Fraction
slamgirl [31]

Step-by-step explanation:

0.345454...... = 4311/9900

0.5888..... = 530/900

0.68080..... = 674/990

4.98585..... = 4936/990

8.18080...... = 8099/990

8 0
3 years ago
Please help simplify and write your answer in the form a + bi
Tcecarenko [31]

Answer:

2 - 4i

Step-by-step explanation:

\frac{10}{1 + 2i}  \\  \\  =  \frac{10}{1 + 2i}  \times  \frac{1  -  2i}{1  -  2i}  \\  \\  =  \frac{10(1 - 2i)}{ {1}^{2} -  {(2i)}^{2}  }  \\  \\   =  \frac{10 - 20i}{ {1} -  {4i}^{2}  }  \\  \\  =  \frac{10 - 20i}{ {1} -  {4( - 1)} }  \\ ( \because \:  {i}^{2} =  - 1)  \\  \\  =  \frac{10 - 20i}{1 + 4} \\  \\  =  \frac{5(2 - 4i)}{5}  \\  \\  = 2 - 4i

5 0
3 years ago
If you answer this, i might give you 3 extra points (:
rodikova [14]
Jewelery maker has
24 jade beads
30 teak Beads
So we need to find the highest common factor for both 24 and 30
The factors for both numbers are
24 -1,2,3,4,6,8,12,24
30 - 1,2,3,5,6,10,15,30
The highest common factor for both is 6
The greatest number of necklaces she can make is 6
Number of jade beads - 24/6 = 4 jade beads
Number of teak beads - 30/6 = 5 teak beads
So each necklace will have 4 jade beads and 5 teak beads
7 0
3 years ago
Read 2 more answers
What is the length of leg y of the right triangle?
xz_007 [3.2K]

Answer:

13

Step-by-step explanation:

We need to use the Pythagorean Theorem to solve this problem:

a^{2} +b^{2} = c^{2} , where a and b are the legs of the right triangle and c is the hypotenuse

In this case, we already know b (b = 84) and c (c = 85), so we need to solve for a:

a^{2} = c^{2} - b^{2} = 85^{2} - 84^{2} = 169 = 13^{2}

Thus, a = y = 13.

4 0
3 years ago
Read 2 more answers
PLEASE HELP ASAP NOO LINKS!!!
storchak [24]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
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