Using 8, 11, 9, 1, and 8 create a problem in which the answer equals 2. You may use operations more than once.

goldfiish [28.3K]

Answer:

The square root of 4096 is 64. The cube root of 4096 is 16. The fourth root of 4096 is 8 and the fifth root is 5.2780316430916.

Step-by-step explanation:

3 0

3 years ago

What is the simplified form of the product. (x+6)(x+4) =

weeeeeb [17]

Answer:

x² + 10x + 24

Step-by-step explanation:

Use foil to multiply them.

x ( x + 4 ) = x² + 4x

6 ( x + 4) = 6x + 24

Combine like terms: x² + 10x + 24

Hope this helps :)

5 0

3 years ago

!!!!!!Please help !!!!!!

Mars2501 [29]

Answer:

II

Step-by-step explanation:

Scatter plots show a negative trend if one value increases as the other decreases.

5 0

3 years ago

Read 2 more answers

marie wants to space markers evenly along a 5-mile race course .she puts a marker at the start line. how far apart should the 21

Ganezh [65]

The marker should be 26400 feet away from the starting point

3 0

3 years ago

a band of 45 ewoks crash-landed in the forest last night. this sounds like a small problem, but the population will grow at the

kogti [31]

Given Information:

Starting population = P₀ = 45

rate of growth = 22%

Required Information:

Population every five years from this year to the year 2050 = ?

Answer:

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Step-by-step explanation:

The population growth can be modeled as an exponential function,

$P(t) = P_0e^{rt}$

Where P₀ is the starting population, r is the rate of growth of the population and t is the time in years.

We are given that starting population of 45 and growth rate of 22%

$P(t) = 45e^{0.22t}$

Assuming that the starting year is 2020,

$Year \: 2020 = P(0) = 45e^{0} = 45\\\\Year \: 2025 = P(5) = 45e^{0.22*5} = 135\\\\Year \: 2030 = P(10) = 45e^{0.22*10} = 406\\\\Year \: 2035 = P(15) = 45e^{0.22*15} = 1,220\\\\Year \: 2040 = P(20) = 45e^{0.22*20} = 3,665\\\\Year \: 2045 = P(25) = 45e^{0.22*25} = 11,011\\\\Year \: 2050 = P(30) = 45e^{0.22*30} = 33,079\\\\$

Therefore, the starting population of ewoks was 45 in 2020 and increased to 33,079 by 2050 in a time span of 30 years.

8 0

3 years ago