Question

Given triangle JKL, sin 38 degree equals

Answer 1

Right triangle
sin(38) = cos(52)

answer
 cos(52)

hope it helps

Answer 2

Answer:

B. $\text{cos}(52^{\circ})$.

Step-by-step explanation:

We have been given a right triangle. We are asked to complete our given statement.

$\text{sin}(38^{\circ})$ equals ___.

We will use identity $\text{sin}(x)=\text{cos}(90-x)$ to solve our given problem.

$\text{sin}(38^{\circ})=\text{cos}(90^{\circ}-38^{\circ})$

$\text{sin}(38^{\circ})=\text{cos}(52^{\circ})$

Therefore, $\text{sin}(38^{\circ})$ equals $\text{cos}(52^{\circ})$.