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4 years ago

PLEASEHELP ASAP THANK YOU SO MUCH

Mathematics

2 answers:

ruslelena [56]4 years ago

8 0

The answer is A: a>= -3 and a <=3

nalin [4]4 years ago

4 0

The answer is the first choice

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Find the solution of this system of equations -3x-7y=-66 -10x-7y=-24

andrezito [222]

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Hi my lil bunny!

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A) Let's solve for x. $-3x-7y=-66$

Step 1: Add 7y to both sides.

$-3x - 7y + 7y = -66 + 7y \\-3x = 7y - 66$

Step 2: Divide both sides by -3.

$\frac{-3x }{-3} = \frac{7y - 66}{-3}$

$x = \frac{-7}{3}y + 22$

Answer : $\frac{-7}{3}y + 22$

~~~~~~~~~~~~~

B) Let's solve for x. $-10x-7y=-24$

Step 1: Add 7y to both sides.

$-10x - 7y + 7y = -24 + 7y \\-10x = 7y - 24$

Step 2: Divide both sides by -10.

$\frac{-10x}{-10} = \frac{7y - 24}{-10}$

$x = \frac{-7}{10}y + \frac{12}{5}$

Answer : $\frac{-7}{10}y + \frac{12}{5}$

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If this helped you, could you maybe give brainliest..?

❀*May*❀

7 0

3 years ago

How many minutes are there in 5/8 of 3 hours

diamong [38]

112.5 minutes

Since there are 60 minutes in 1 hour so multiply that by 3 and you get 180 minutes
180➗8=22.5
22.5✖️5= 112.5 minutes

Hope this helps! :3

8 0

3 years ago

Read 2 more answers

a pizzeria had 4 cans of tomato sauce how many pizzas could they make with the cans if each pizza took one fourth of a can

Murrr4er [49]

Answer:

16 pizzas.

Step-by-step explanation:

That is 4 divided by 1/4

= 4 * 4/1

= 16.

7 0

3 years ago

Read 2 more answers

Lim n-> infinity [1/3 + 1/3² + 1/3³ + . . . .+ 1/3ⁿ]

Verizon [17]

Answer:

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm :\longmapsto\:\displaystyle\lim_{n \to \infty }\rm \bigg[\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } \bigg]$

Let we first evaluate

$\rm :\longmapsto\:\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} }$

Its a Geometric progression with

$\rm :\longmapsto\:a = \dfrac{1}{3}$

$\rm :\longmapsto\:r = \dfrac{1}{3}$

$\rm :\longmapsto\:n = n$

So, Sum of n terms of GP series is

$\rm :\longmapsto\:S_n = \dfrac{a(1 - {r}^{n} )}{1 - r}$

$\rm :\longmapsto\:S_n = \dfrac{1}{3} \bigg[\dfrac{1 - {\bigg[\dfrac{1}{3} \bigg]}^{n} }{1 - \dfrac{1}{3} } \bigg]$

$\rm :\longmapsto\:S_n = \dfrac{1}{3} \bigg[\dfrac{1 - {\bigg[\dfrac{1}{3} \bigg]}^{n} }{\dfrac{3 - 1}{3} } \bigg]$

$\rm :\longmapsto\:S_n = \dfrac{1}{3} \bigg[\dfrac{1 - {\bigg[\dfrac{1}{3} \bigg]}^{n} }{\dfrac{2}{3} } \bigg]$

$\bf\implies \:S_n = \dfrac{1}{2}\bigg[1 - \dfrac{1}{ {3}^{n} } \bigg]$

Hence, 

$\bf :\longmapsto\:\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } = \dfrac{1}{2}\bigg[1 - \dfrac{1}{ {3}^{n} } \bigg]$

Therefore, 

$\purple{\rm :\longmapsto\:\displaystyle\lim_{n \to \infty }\rm \bigg[\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } \bigg]}$

$\rm \: = \: \displaystyle\lim_{n \to \infty }\rm \dfrac{1}{2}\bigg[1 - \dfrac{1}{ {3}^{n} } \bigg]$

$\rm \: = \: \rm \dfrac{1}{2}\bigg[1 - 0 \bigg]$

$\rm \: = \: \rm \dfrac{1}{2}$

Hence, 

$\purple{\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{n \to \infty }\rm \bigg[\dfrac{1}{3} + \dfrac{1}{ {3}^{2} } + \dfrac{1}{ {3}^{3} } + - - + \dfrac{1}{ {3}^{n} } \bigg]} = \frac{1}{2}}}$

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<h3>Explore More</h3>

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{sinx}{x} = 1}}$

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{tanx}{x} = 1}}$

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{log(1 + x)}{x} = 1}}$

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{ {e}^{x} - 1}{x} = 1}}$

$\rm :\longmapsto\:\boxed{\tt{ \displaystyle\lim_{x \to 0}\rm \frac{ {a}^{x} - 1}{x} = loga}}$

8 0

3 years ago

How much would you pay for 3.5 pounds of bananas at a price of $0.90 per pound

REY [17]

Answer:

y=3.5+0.90x

Step-by-step explanation:

are you trying to find the equation?? if so this is the equation

8 0

4 years ago