Yes it is easy to do if u need help message me
Answer:
what exactly are you trying to do?
Step-by-step explanation:
find how long a line is?
find out the area or perimeter
m = ![\frac{29}{18}](https://tex.z-dn.net/?f=%5Cfrac%7B29%7D%7B18%7D)
add
to both sides
m = -
+ ![\frac{11}{6}](https://tex.z-dn.net/?f=%5Cfrac%7B11%7D%7B6%7D)
we require a common denominator for both fractions before adding
multiply numerator/denominator of -
by 2
multiply the numerator/denominator of
by 3
= -
+
= ![\frac{29}{18}](https://tex.z-dn.net/?f=%5Cfrac%7B29%7D%7B18%7D)
The two equations are equivalent.
The postage for 3 posters is $5.
Lois$ wrote an expression for the total they both spent as 6x + 10 6(25) +10
150 +10 = 160
Clark wrote another expression for the total, saying that it represented the same cost: 2(3x + 5). = 2(3x) + 2(5) 6x + 10 = 6(25) + 10 = 150+10 160
If each poster costs $25, do the two expressions give the same amount?
Your statement is not clear.
still if ∅=45
and ∅ lies in 4th quadrant.
csc&cot are negative in 4th quadrant.
csc ∅=1/sin ∅=1/+-sqrt(1-cos^2 ∅)
=-1/sqrt(1-cos^245)
=-1/sqrt(1-(1/√2)^2)
=-1/√(1-1/4)
=-1/√(3/4)
=-2/√3
cot ∅=cos ∅/sin∅=cos315/sin315=cos(360-45)/sin (360-45)
=cos 45/-sin 45=-1