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Nimfa-mama [501]
3 years ago
8

A hiker whose eyes are 5.5 feet above the ground stands 25 feet from the base of a redwood tree. She looks up at an angle of 71

degrees to see the top of the tree. To the nearest tenth of a foot, what is the height of the tree?
Mathematics
2 answers:
borishaifa [10]3 years ago
8 0
Tan of a 71 degree angle = 71 tan/1=72 feet + 5.5 feet (because of the height of the hiker's eyes) = 78.1 feet
Leokris [45]3 years ago
3 0
If you draw out a diagram of the situation, the height of the person is 5.5 feet, standing 25 feet away from the tree. then the person looks up at a 71 degree angle with the top of the tree, it should look like a right triangle on top of a rectangle. 

We know the angle she's looking at (71 degrees) and the side adjacent to the angle (the distance she is away from the tree, 25 feet). Using tangent we can solve for the opposite side. 

tan(71 degrees) = x ÷ 25
25 tan (71 degrees) = x
x is about 72.6 feet 

that's the height from her eyes to the top of the tree. 
To get the height of the tree you add how high above the ground her eyes are (5.5 feet) to x (72.6 feet) 

72.6 + 5.5 = 78.1 feet

that should be the height of the tree
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erma4kov [3.2K]
Solving for x.

Since x<span> is on the right-hand side of the </span>equation<span>, switch the sides so it is on the left-hand side of the </span>equation<span>.
</span><span>0.04<span>x2</span>−8.504x+25302=c

</span>Simplify the quadratic and set<span> the right side equal to </span><span>0.
</span><span>0.04<span>x2</span>−8.504x+25302−c=0

</span>Use the standard form of the quadratic <span>(<span><span>a<span>x2</span>+bx+c</span>)</span></span><span> to find </span><span>a,</span><span>b,</span><span> and </span>c<span> for this quadratic.
</span><span>a=0.04,</span><span>b=−8.504,</span><span>c=25302−1c

</span>Use the quadratic formula<span> to find the </span>solutions<span>.
</span><span>x=<span>−b ± </span></span>√<span><span> <span><span>b2</span>−4ac /</span> </span><span>2a

</span></span>Substitute in the values of <span><span>a=0.04</span>,</span><span><span>b=−8.504</span>,</span><span> and </span><span><span>c=25302−1c</span>.
</span>x=<span>−(−8.504) ±</span>√<span><span>(−8.504<span>)2</span>−4(0.04)(25302−1c)/</span><span>2(0.04)
</span></span>
<span>Simplify.
</span>x=<span>8.504 ±</span>√<span><span>(−8.504<span>)2</span>−4(0.04)(25302−1c)/</span><span>2(0.04)
</span></span>
Simplify the section inside the radical<span>.
</span>x=<span>8.504 ± </span>√<span><span><span>−3976.001984+0.16c</span>/</span><span>2(0.04)
</span></span>
Simplify the denominator<span> of the </span>quadratic formula<span>.
</span>x=<span>8.504 ±</span>√<span><span>−3976.001984+0.16c/</span>0.08
</span>

Answer:
x=8.504 ±√−3976.001984+0.16c/0.08


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Plane 1 is 176.27 miles away, and plane 2 is 222.34 miles away. The angle formed with the tracking station is 38.59*. What is th
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We know that
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