Y = t*e^(-t/2)
y' = t' [e^(-t/2)] + t [e^(-t/2)]' = e^(-t/2) + t[e^(-t/2)][-1/2]=
y' = [e^(-t/2)] [1 - t/2] = (1/2)[e^(-t/2)] [2 - t] = - (1/2) [e^-t/2)] [t -2]
The answer should be A because point slope form is y-y1=m(x-x1)....M is the starting point and its -56 and y1(-4) is the y value of the coordinate point and x1(8) is the x value of the coordinate point. it changes to y+4 because two negative signs make a positive(y--4)
Answer:
-4.1, -3.5, -1.4, 5.3
Step-by-step explanation:
hope this helps!
The answer would be -12q^4
Answer:
Yes, La Tasha is correct, because the correlation coefficient is r=0
Step-by-step explanation:
Please, see the attached file.
Thanks.
