Write the equation of the line that passes through (3, 4) and (2, –1) in slope-intercept form.

1 answer:

5 0

1) slope is 6 and y-intercept is ( 0,5) y = mx + b, m = 6, b = 5 y = 6x + 5 2)line passes through the points ( 3,6) and ( 6,3 ) First find the slope: m = (3-6)/(6-3) = -3/3 = -1 y = -x + b Plug in one of the given points (x,y) and find b 6 = -3 + b 9 = b <span> y = -x + 9</span> a horizontal line that passes through the point ( -1,7)Horizontal lines have a constant y-value and formaty = c where c is a constant number. y = 7 y=-3x+3x intercept: set y = 0 and solve for x0 = -3x + 33x = 3x = 1x-intercept: (1, 0) y-intercept: set x = 0 and solve for yy = -3(0) + 3y = 3y-intercept: (0,3) y=0,5x-1Is this two equations? The line y=0 has y-intercept at (0,0)The x-intercept is the entire x-axis y=5x-1x -intercept: Set y = 0 and solve for x y-intercept: Set x = 0 and solve for y

You might be interested in

My grade is a 77%, if i get a 0% on a paper worth 30% of my grade, what will my grade be now??

blsea [12.9K]

$Grade=Paper+Other$
$Grade=(Grade_{paper}\times Value_{paper})+(Grade_{other}\times Value_{other})$
$Grade=(0 \times 30\%)+(77\% \times (1-30\%))$
$Grade=(0 \times 30\%)+(77\% \times 70\%)$
$Grade=0+53.9\%$
$Grade=53.9\%$