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sergij07 [2.7K]
3 years ago
8

To find amplitude, measure (blank). A. the horizontal distance between consecutive crest positions B. the horizontal distance be

tween a consecutive crest and trough C. the vertical distance from a crest to a trough D. the vertical distance from a crest to the rest position
Mathematics
2 answers:
Oksanka [162]3 years ago
5 0
The vertical distance from a crest to the rest position ! I know I'm a little late but I just took this.
masya89 [10]3 years ago
5 0
The vertical distance from the crest to the rest position.
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Help me with this exercise
Vinil7 [7]
<em>The answer you are looking for is: </em>
<em><u>270 yards^{2} </u></em>
<em><u>15*18= 270 </u></em>
<em><u>And you have to add the yard square at the end. </u></em>
<em>Hope that helps!! </em>
<em>Have a wonderful day!!</em><span />
6 0
2 years ago
Why is the answer to this integral's denominator have 1+pi^2
ss7ja [257]

It comes from integrating by parts twice. Let

I = \displaystyle \int e^n \sin(\pi n) \, dn

Recall the IBP formula,

\displaystyle \int u \, dv = uv - \int v \, du

Let

u = \sin(\pi n) \implies du = \pi \cos(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Then

\displaystyle I = e^n \sin(\pi n) - \pi \int e^n \cos(\pi n) \, dn

Apply IBP once more, with

u = \cos(\pi n) \implies du = -\pi \sin(\pi n) \, dn

dv = e^n \, dn \implies v = e^n

Notice that the ∫ v du term contains the original integral, so that

\displaystyle I = e^n \sin(\pi n) - \pi \left(e^n \cos(\pi n) + \pi \int e^n \sin(\pi n) \, dn\right)

\displaystyle I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n - \pi^2 I

\displaystyle (1 + \pi^2) I = \left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n

\implies \displaystyle I = \frac{\left(\sin(\pi n) - \pi \cos(\pi n)\right) e^n}{1+\pi^2} + C

6 0
2 years ago
32) (a)-(c) pre calculus
Harrizon [31]
Well, remember we can't take the square root of a negative

so we see that we have \sqrt{1-x^2}
so find those values that take sqrt of a negative and restrict hem from the domain
anny value greater than 1 and less than -1
so domain is from -1 to 1, including those numbers
D=[-1,1]

a. D=[-1,1] or from -1 to 1 is domain


b. for a TI-84, go to y-editor then input 4x \sqrt{1-x^2} for y1

c. for a TI-84, click 2nd then window (gets to tbset) scrol down to set Δx to 0.1, then cilick 2nd again then click graph (to select table) and scroll down till you see that value of y that is the biggest, that value is x=0.7



A. domain is from -1 to 1
B. use your brain or google the instructions for your calulator
C. at x=0.7


8 0
3 years ago
12.   Paul bought 9 total shirts for a total of $72. Tee shirts cost $10 and long sleeve shirts cost $7. How many of each type o
iragen [17]
6 camisas de manga larga y 3 camisetas



3 0
3 years ago
Read 2 more answers
Pls answer<br> Subtract -37 from -53
scZoUnD [109]

Answer:

-37 subtract -53

-53 subtract -37 = -16

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
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