All categories

3 years ago

How is this solved?

d="TexFormula1" title=" f{x} = \frac{2x + 1}{x + 1?} " alt=" f{x} = \frac{2x + 1}{x + 1?} " align="absmiddle" class="latex-formula">

Mathematics

1 answer:

bekas [8.4K]3 years ago

7 0

$\bf f(x)=\cfrac{2x+1}{x+1}\implies \stackrel{f(x)}{0.3}=\cfrac{2x+1}{x+1}\implies 0.3(x+1)=2x+1
\\\\\\
0.3x+0.3=2x+1\implies 0.3x-2x=1-0.3\implies 0.3x-2x=0.7
\\\\\\
-1.7x=0.7\implies x=\cfrac{0.7}{-1.7}\implies x\approx -0.41176470588235294$

You might be interested in

Find the explicit formula for the given sequence.

DedPeter [7]

Answer:

Step-by-step explanation:

given the sequence above using using two as a first term the only formula fits the sequence above is A

7 0

3 years ago

Read 2 more answers

Keenan buys an embroidery machine for $1,400. He uses it to embroider T-shirts. His total profit in dollars from selling the T-s

Romashka [77]

Answer:

the graph shift down 135 units

Step-by-step explanation:

when there is no fixing cost:

f(x)=12x-1400

when there is fixing cost (0ne time): 12x-(1400+135)

the graph shift down 135 units

7 0

3 years ago

PLEEEEEEEAAAAAAASSSSSSSSSSEEEEEEEEEEE help me!!!!!!!!!!

defon

Answer:

$\boxed{\sf \ \ \ \dfrac{18}{(x-7)(x+12)(x+30)} \ \ \ }$

Step-by-step explanation:

hello,

first of all we will study the quadratic expressions

we can write that, (the different answers provide good clues :-) )

$x^2+5x-84=(x-7)(x+12)$

and

$x^2+23x-210=(x-7)(x+30)$

so first of all as we cannot divide by 0 we need to take x different from 7, -12 and -30 and then we can write

$\dfrac{1}{x^2+5x-48}-\dfrac{1}{x^2+23x-210}=\dfrac{1}{(x-7)(x+12)}-\dfrac{1}{(x-7)(x+30)}\\\\=\dfrac{(x+30) -(x+12)}{(x-7)(x+12)(x+30)}=\dfrac{x+30-x-12}{(x-7)(x+12)(x+30)}\\\\=\dfrac{18}{(x-7)(x+12)(x+30)}$

hope this helps

7 0

3 years ago

ABC is an isosceles triangle in which ab and ac are equal if d is a the midpoint of BC prove that ABD=ADC

jeka94

Answer:

Step-by-step explanation:

Given that,

ABC is an Isosceles triangle.

In an Isosceles triangle the opposite sides ( AB =AC) are equal; Their base angles ( < ABD = < ACD) are also equal to each other.

It is als given that D is the mid point of BC.

i.e., BD = CD

Therefore,

By SAS theorem of congruency of triangles,

ABD = ACD

If this is the answer required, hope it helps...

4 0

3 years ago

eric studied for 17.5 hours for a period of 4.5 days. On the average, how much did he study each day?

deff fn [24]

17. 5/4.5 = apx. 3.89

Hope this helps!

7 0

4 years ago