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3 years ago

a science fair poster is a rectangle 48 inches long and 24 inches wide what is the area of the poster in square feet

Mathematics

2 answers:

anzhelika [568]3 years ago

8 0

Answer:

Area=B×H=48×24=1,152 inches^2

victus00 [196]3 years ago

3 0

1 ft = 12 inches
2 ft = 24 inches
4 ft = 48 inches

The poster is 4 ft by 2 ft, so has an area of
(4 ft)×(2 ft) = 8 ft²

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aleksandrvk [35]

Answer:

Part 1) $FG=4.4\ units$

Part 2) $EF=3.9\ units$

Part 3) $m\angle G=63^o$

Step-by-step explanation:

step 1

Find the measure of length side FG

In the right triangle EFG

we know that

$sin(27^o)=\frac{GE}{FG}$ ----> by SOH (opposite side divided by the hypotenuse)

substitute the given values

$sin(27^o)=\frac{2}{FG}$

$FG=\frac{2}{sin(27^o)}=4.4\ units$

step 2

Find the measure of length side EF

In the right triangle EFG

we know that

$cos(27^o)=\frac{EF}{FG}$ ----> by CAH (adjacent side divided by the hypotenuse)

substitute the given values

$cos(27^o)=\frac{EF}{4.4}$

$EF=cos(27^o)(4.4)=3.9\ units$

step 3

Find the measure of angle G

we know that

$m\angle G+27^o=90^o$ ---> by complementary angles in a right triangle

$m\angle G=90^o-27^o=63^o$

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3 years ago

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Nastasia [14]

Answer:

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Step-by-step explanation:

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Ulleksa [173]

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nikitadnepr [17]

Answer:

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