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Pavel [41]
3 years ago
12

How do you get the answer 1 and 1/4-3/8

Mathematics
1 answer:
JulijaS [17]3 years ago
5 0
U first find the common denominator which is 8

Then subtract to get 7/8

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PLZ ASAP! but take your time to solve it.
gizmo_the_mogwai [7]

Answer:

20

Step-by-step explanation:

6 0
3 years ago
DUE SOON PLEASE HELP
swat32

Answer:

Im pretty sure its 114 m^2 sorry if im wrong

4 0
3 years ago
Read 2 more answers
In triangle $ABC$, let angle bisectors $BD$ and $CE$ intersect at $I$. The line through $I$ parallel to $BC$ intersects $AB$ and
Umnica [9.8K]

Answer:

41

Step-by-step explanation:

If you work through a series of obscure calculations involving area and the radius of the incircle, they boil down to a simple fact:

... For MN║BC, perimeter ΔAMN = perimeter ΔABC - BC = AB+AC

.. = 17+24 = 41

_____

Wow! Thank you for an interesting question with a not-so-obvious answer.

_____

<em>A little more detail</em>

The point I that you have defined is the incenter—the center of an inscribed circle in the triangle. Its radius is the distance from I to any side, such as BC, for example.

If we use "Δ" to represent the area of the triangle and "s" to represent the semi-perimeter, (AB+BC+AC)/2, then the incircle has radius Δ/s. The area Δ can be computed from Heron's formula by ...

... Δ = √(s(s-a)(s-b)(s-c)) . . . . where a, b, c are the side lengths

For this triangle, the area is Δ = √38480 ≈ 196.1632 units². That turns out to be irrelevant.

The altitude to BC will be 2Δ/(BC), so the altitude of ΔAMN = (2Δ/(BC) -Δ/s). Dividing this by the altitude to BC gives the ratio of the perimeter of ΔAMN to the perimeter of ΔABC, which is 2s.

Putting these ratios and perimeters together, we get ...

... perimeter ΔAMN = (2Δ/(BC) -Δ/s)/(2Δ/(BC)) × 2s

... = (2/(BC) -1/s) × BC × s = 2s -BC

... perimeter ΔAMN = AB +AC

8 0
3 years ago
Solve the equation for the indicated variable S=2πrh+2πr²<br> Solve for h
valina [46]

Answer:

Good luck :)

Step-by-step explanation:

S=2πrh+2πr ²

subtract 2πr ² from each side

S -2πr ² = 2πrh

divide by 2πr from each side

(S -2πr ² )/ 2πr  = h

4 0
3 years ago
Which ordered pair would form a proportional relationship with the point graphed below? (60,-20)
valentina_108 [34]

Given:

The graphed point is (60,-20).

To find:

The ordered pair that would form a proportional relationship with the given point.

Solution:

If y is proportional to x, then

y\propto x

y=kx

\dfrac{y}{x}=k

Where, k is the constant of proportionality.

For the given point,

k=\dfrac{-20}{60}

k=\dfrac{-1}{3}

For option (A),

k=\dfrac{30}{-10}

k=-3\neq \dfrac{-1}{3}

For option (B),

k=\dfrac{-15}{30}

k=-\dfrac{1}{2}\neq \dfrac{-1}{3}

For option (C),

k=\dfrac{10}{-30}

k=\dfrac{-1}{3}.

The point (-30,10) gives the same value of the constant of proportionality. So, the point (-30,10) forms a proportional relationship with the given point.

Therefore, the correct option is C.

7 0
3 years ago
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