One Question Please Help

Mathematics

1 answer:

grandymaker [24]3 years ago

5 0

Since CE bisects BED then < BEC = <CED = 4x + 1
Add them all together.
<AEB + <BEX + <CED = 180
11x - 12 + 4x + 1 + 4x + 1 = 180
Collect the left terms on the left.
19x - 10 = 180 Add 10 to both sides.
19x = 180 + 10
19x = 190 Divide by 19
x = 190/19
x = 10

That is not the answer. The answer is
4x + 1
4*10 + 1
40 + 1
BEC = 41 <<<<<=====

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3 years ago

For each value of U, determine whether it is a solution,

abruzzese [7]

Given u/7 - 1 = 7 and plugging in values for u,

For u = 28; 28/7 - 1 = 4 - 1 = 3; No
For u = -49; -49/7 - 1 = -7 - 1 = -8; No
For u = 42; 42/7 - 1 = 6 - 1 = 5; No
For u = 0; 0/7 - 1 = -1; No

Another way to find out which value would be a solution to u/7 - 1 = 7 is to solve for u.

u/7 - 1 = 7
u/7 = 7 + 1
u/7 = 8
u = 8*7
u = 56

The only solution to this equation is when u = 56.

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3 years ago

Solve the equation. 25-3x=40 what does x equal?

9966 [12]

Answer:

x=-5

Step-by-step explanation:

25 - 3x = 40

-3x + 25 =40

-3x +25--25=40-25

-3x=15

-3x÷-3=25÷-3

x=-5

6 0

3 years ago

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Arrange the equations in the correct sequence to rewrite the formula for displacement, , to find a. In this formula, d is displa

valina [46]

Answer:

$a=2[d-V_0t]/t^2=2d/t^2-2v_0/t$

Explanation:

Since, you have not included the formula, I will work here with the formula for constant accelaration motion that relates the four variables: displacement (d), Vo (initial velocity), a (acceleration) and t (time).

1) displacement formula:

$d= V_0t+\frac{1}{2} at^2$

2) Subtract the term Vot from both sides:

$d-V_0t= \frac{1}{2} at^2$

3) Multiply both sides by 2:

$2d -2V_0t=at^2$

4) Divide both sides by t²

$2[d-V_0t]/t^2=a$

So, you have obtainded:

a = 2[d - Vo×t] / t²

Yet, you can arrange it in different ways. For example, you might separate into two terms:

$a = \frac{2d}{t^2} - \frac{2V_0}{t}$

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3 years ago

8/9 x 1/12 = simplified

egoroff_w [7]

2/27

Hope it helps and please make mine the Brainliest answer!

3 0

4 years ago

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