Answer:
Step-by-step explanation:
Quadrilateral EFGH is a rectangle.
Therefore, measure of all interior angle of the rectangle = 90°
7). m∠FEG + m∠GEH = 90°
57° + m∠GEH = 90°
m∠GEH = 90° - 57°
m∠GEH = 33°
Diagonal of the rectangle are equal in measure and bisect each other.
8). m(FH) = m(FK) + m(KH)
= 32 + 32 [Since, FK ≅ KH]
= 64
9). m∠FGH + m∠EFG = 90° + 90°
= 180°
MNOP is a Rhombus, so the diagonals will be perpendicular and bisect each other.
10). m∠MRN = 90°
11). m(PR) = 12
Therefore, m(RN) = 12
"Diagonals of a rhombus bisect the opposite angles"
12). m(∠PON) = 124°
Therefore, m(∠POM) = 124°
"ABCD is an isosceles Trapezoid"
13). Therefore, ∠C ≅ ∠D
14). AB║CD
15). AD ≅ BC
