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2 years ago

Can someone help me with this?

Mathematics

1 answer:

oksano4ka [1.4K]2 years ago

6 0

Answer:

Step-by-step explanation:

Quadrilateral EFGH is a rectangle.

Therefore, measure of all interior angle of the rectangle = 90°

7). m∠FEG + m∠GEH = 90°

57° + m∠GEH = 90°

m∠GEH = 90° - 57°

m∠GEH = 33°

Diagonal of the rectangle are equal in measure and bisect each other.

8). m(FH) = m(FK) + m(KH)

= 32 + 32 [Since, FK ≅ KH]

= 64

9). m∠FGH + m∠EFG = 90° + 90°

= 180°

MNOP is a Rhombus, so the diagonals will be perpendicular and bisect each other.

10). m∠MRN = 90°

11). m(PR) = 12

Therefore, m(RN) = 12

"Diagonals of a rhombus bisect the opposite angles"

12). m(∠PON) = 124°

Therefore, m(∠POM) = 124°

"ABCD is an isosceles Trapezoid"

13). Therefore, ∠C ≅ ∠D

14). AB║CD

15). AD ≅ BC

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<h3>RIGHT TRIANGLE</h3>

A triangle is classified as a right triangle when it presents one of your angles equal to 90º. The greatest side of a right triangle is called hypotenuse. And, the other two sides are called cathetus or legs.

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Learn more about trigonometric ratios here:

brainly.com/question/11967894

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