A laboring client who is positive for Group B Streptococcus is given an initial dose of ampicillin (Omipen) 2 g at 9 am. Accordi
1 answer:
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Answer:
1. 45.9 to 62 kg.
2. 82.72 %
Explanation:
1. We have to find out Mr. Swanson's body weight by calculating his body mass index.
From body mass index or BMI = weight of the person in kg / height in meter
BMI = 41.36/ 1.5748
= 41.36 /2.47999504
= 16.67
The normal range of BMI is 18.5 to 24.9. So, Ms. Swanson's desirable body weight would be 45.9 to 62 kgs.
2. Mr. Swanson's percent ideal body weight:
=
Now calculating the ideal body = 45.5 kg + 2.3 kg for each inch above 5 feet
Ideal body weight (IBW) = 45.5 + 2.3 x 2
= 50 kg
Now calculating the percentage ideal body weight
=
= 0.8272 x 100
= 82.72 %
The normal range of percentage ideal body weight lies between 90 - 100 percent. Thus, the percentage ideal body weight of Mr. Swanson is low.
3. Some of the physical signs that can be seen in the patient when the patient is dehydrated are :
i). Dry skin
ii). weight loss
iii). thirsty
iv). pale skin color
v). fatigue
vi). tiredness
vii). dizziness
4. The transthyretin of Mr. Swanson is quite low and it indicates malnutrition. His transthyretin is about 15mg/dl. Thus he require proper diet planning and modifications.
5. Mr. Swanson must take in high calorie food and should consume plenty of water. She should also include fibers in her food intake. Mr. Swanson should consult a nutritionist or a dietitian who could properly guide her and make a food chart that includes daily intake of nutritious and protein rich food.
6. For increasing the food intake, Mr. Swanson must follow a healthy diet. He should take small servings but many times a day. Also exercising and drinking plenty of water will increase his food intake and will keep him healthy.