Answer:
no solutions
Step-by-step explanation:
For this case we have the following equation of motion:
h (t) = -16t ^ 2 + 90t
Equaling the equation to zero we have:
-16t ^ 2 + 90t = 0
We look for the roots of the polynomial:
(t) (- 16t + 90) = 0
t1 = 0 (initial position)
t2 = 90/16 = 5.625 s (time it reaches the ground again)
Answer:
it will return to the ground in:
t = 5.625 s
Answer:
Step-by-step explanation:
answerrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrrr =====8
Answer:
If:
(1)
And we have to rewrite the following expresion in terms of 
:
(2)
Firstly we have to rearrange the right side of equation (2) in terms of 
, factorizing by the common factor:
Then, we can substitute by :
And set it equal to zero:
>>>>This is the resulting equation
Now, each term of an algebraic expresion (like the equation above) is composed of sign, coefficient, variable and exponent. The terms are separated from each other by the plus sign (+) or the minus sign (-).
In this case, the variable is and the number that multiplies the variable (the coefficient) is 
, whereas the constant (which is the term with no variable) is 
Answer:
Step-by-step explanation:
The equation of a circle of radius r, centered at the point (a,b) is
We already know the center is at 
, we are just missing the radius. To find the radius, we can use the fact that the circle passes through the point (7,4), and so the radius is just the distance from the center to this point (see attached image). So we find the distance by using distance formula between the points (7,4) and (4,-5):
radius
And now that we know the radius, we can write the equation of the circle:
