Help me solve this please. I don't know the formula for this.

Simplify 8^x/4^y x 2^z

Lera25 [3.4K]

Answer:

The answer is 8x.

Step-by-step explanation:

It is 8x.

EXCEPT,

Is it $2^{z}$ or $2^{2}$

If it is $2^{z}$ then the answer is $\frac{2^{3x+z} }{4}$

PLEASE MARK BRAINLIEST

4 0

3 years ago

A 7th-grade class has 14 girls and 10 boys. An 8th-grade class has 11 girls and 13 boys. What is the probability of picking a st

melomori [17]

Answer:

14>10 11<13

Step-by-step explanation:

4 0

3 years ago

to build the garden of your dreams you need 11 m^3 of coil containing 46% clay. you have two types of soil you can combine to ac

aivan3 [116]

Answer: 9m^3 of soil with 50% clay and 2m^3 of soil with 28% clay is required

Step-by-step explanation:

Let x represent the quantity of the soil containing 50% clay that you would use.

Let y represent the quantity of the soil containing 28% clay that you would use.

To build the garden of your dreams you need 11 m^3 of soil.

x + y = 11 - - - - - - - - -1

Since the soil must contain 46% clay, the total amount of clay required is 46/100 × 11 = 5.06 m^3.

you have two types of soil you can combine to achieve this: soil with 50% clay and soil with 28% clay. This means that the quantity of both soils required to achieve 5.06 m^3 will be

0.5x + 0.28y = 5.06 - - - - - - - -2

Substituting x = 11 - y into equation 1, it becomes

0.5(11 - y) + 0.28y = 5.06

5.5 - 0.5y + 0.28y = 5.06

- 0.5y + 0.28y = 5.06 - 5.5

- 0.22y = - 0.44

y = - 0.44/ -0.22 = 2

Substituting y = 2 into x = 11 - y, it becomes

x = 11 - 2 = 9

7 0

4 years ago

A tobacco company claims that the amount of nicotene in its cigarettes is a random variable with mean 2.2 and standard deviation

Aleksandr-060686 [28]

Answer:

0% probability that the sample mean would have been as high or higher than 3.1 if the company’s claims were true.

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$