We have to choose the correct answer which of the employees has the greatest total employee compensation. We just have to subtract the job expenses from total job benefits for everyone of them. A: $49,200 - $300 = $38,900. B : $49,500 - $500 = $49,000. C : $49,800 - $700 = $41,100. D : $50,100 - $900 = $49,200. The largest sum is $49,200 ( employee D ) . Answer: The greatest total employee compensation has Employee D<span>.</span>
Slope is known as rise over run. Because the line is pointing "\", it is negative.
The rise, the distance from one point to another, specifically from (0,4) to (1,1) is 3, as 4-1=3. your run is 1-0=1.
So your rise over run is -3/1 or, -3.
Your y-int is where when x=0, y=?
In this case y=4 when x=0.
Your equation is
y=-3x+4
Answer:
y = 1/2x - 4
Step-by-step explanation:
If two lines are perpendicular to each other, they have opposite slopes.
The first line is y = -2x + 8. Its slope is -2. A line perpendicular to this one will have a slope of 1/2.
Plug this value (1/2) into your standard point-slope equation of y = mx + b.
y = 1/2x + b
To find b, we want to plug in a value that we know is on this line: in this case, it is (4, -2). Plug in the x and y values into the x and y of the standard equation.
-2 = 1/2(4) + b
To find b, multiply the slope and the input of x (4)
-2 = 2 + b
Now, subtract 2 from both sides to isolate b.
-4 = b
Plug this into your standard equation.
y = 1/2x - 4
This equation is perpendicular to your given equation (y = -2x + 8) and contains point (4, -2)
Hope this helps!
Answer:
Lower limit: 113.28
Upper limit: 126.72
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Middle 60%
So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8
Lower limit
X when Z has a pvalue of 0.20. So X when 




Upper limit
X when Z has a pvalue of 0.80. So X when 




Answer:
<h2> 52 chickens</h2>
Step-by-step explanation:
Step one:'
given
we are told that the total number of animals is 169
the ratio of horses to chickens= 9:4
total ratio= 13
Required:
number of chickens
Applying part to all principle, let the number of chickens be x
4/13=x/169
cross multiply
4*169=13*x
divide both sides by 13
x=4*169/13
x=676/13
x=52
There are 52 chickens