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wlad13 [49]
2 years ago
14

Tomas learned that the product of the polynomials

rmula1" title="(a+b)(a^2-ab+b^2)" alt="(a+b)(a^2-ab+b^2)" align="absmiddle" class="latex-formula"> was a special pattern that would result in a sum of cubes, a^3+b^3.
His teacher put four products on the board and asked the class to identify which product would result in a sum of cubes if a=2x and b=y.
Mathematics
1 answer:
Liula [17]2 years ago
3 0

We are provided , Tomas learned <em><u>that a³ + b³ = (a + b ) ( a² - ab + b² )</u></em> , and his teacher writes four products on the board and we have to tell that which product suits the best if <em><u>a = 2x</u></em> and <em><u>b =</u></em><em><u> </u></em><em><u>y</u></em>

Now , putting a = 2x , b = y in the given formula we have :

{:\implies \quad \sf (2x)^{3}+(y)^{3}=(2x+y)\{(2x)^{2}-2\cdot x\cdot y+(y)^{2}\}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(2x)^{3}+(y)^{3}=(2x+y)(4x^{2}-2xy+y^{2})}}}

Hence , The product <em>(2x+y) (4x²-</em><em>2</em><em>xy+y²)</em> would result in the sum of cubes of 2x & y :D

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4. 46 is what percent of 69?
sergij07 [2.7K]

Answer:

66%(technically 0.66 repeating)

Step-by-step explanation:

We need to figure out what percentage of 69 equates to 46. In other words, we need to figure out what percentage <u>times</u> 69 equals 46:

percentage*69 = 46

Now that we formed this equation, we can solve for the percentage as if it was x.

First lets simplfy:

percentage*69 = 46 -- > 69percentage = 46

Now we can solve for x just by getting x alone, which means we must remove the coefficent. We can do this by dividing both sides of the equation by 69:

percentage = \frac{46}{69}

=

percentage=0.66

Putting this into the form of percentage, we must multiply by 100. Since, the percentage form of a decimal is 100 times bigger(moved up 2 decimal places):

percentage = 0.66*100

=

percentage = 66%

Hope this helps! :3

4 0
2 years ago
WILL GIVE BRAINLIEST FOR A CORRECT ANSWER:
guapka [62]

Answer:

Solution:

the boat's speed in still water: x

The speed with current: (x+3)

The speed against current: (x-3)

The equation is

3(x+3) = 4(x-3)

x = 21 mph

The distance = 3*(21+3)= 72 miles

I  choose (A)

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
WILL GIVE BRAINLIEST THANKS AND 5 STARS FOR CORRECT ANSWER Desmond ran a lemonade stand in front of his house for the fans walki
Fiesta28 [93]

Answer:

56

Step-by-step explanation:

First, convert the 70% so that we can use it with the 80 cups. To do this, convert the percent to a decimal by moving the decimal 2 spaces to the left:

70% → 70.00 → 0.70 → 0.7

70% percent can be seen as 0.7. Multiply this by 80:

80*0.7=56

So, 70% of 80 is 56. Desmond sold 56 cups on the second Saturday.

:Done

7 0
3 years ago
Find inequalities with solutions that have this graph.
Oduvanchick [21]
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8 0
3 years ago
Coach Evans recorded the height, in inches of each player on his team. The results are shown.
marysya [2.9K]

Answer:

3

Step-by-step explanation:

Given:

Team heights (inches):

61, 57, 63, 62, 60, 64, 60, 62, 63

To find: IQRs (interquartile ranges) of the heights for the team

Solution:

A quartile divides the number of terms in the data into four more or less equal parts that is quarters.

For a set of data, a number for which 25% of the data is less than that number is known as the first quartile (Q_1)

For a set of data, a number for which 75% of the data is less than that number is known as the third quartile (Q_3)

Terms in arranged in ascending order:

57,60,60,61,62,62,63,63,64

Number of terms = 9

As number of terms is odd, exclude the middle term that is 62.

Q_1 is median of terms 57,60,60,61

Number of terms (n) = 4

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{60+60}{2}=\frac{120}{2}=60

So, Q_1=60

So, 25% of the heights of a team is less than 60 inches

Q_3 is the median of terms 62,63,63,64

Median = \frac{(\frac{n}{2})^{th} +(\frac{n}{2}+1)^{th}  }{2} =\frac{2^{nd}+3^{rd}}{2} =\frac{63+63}{2}=\frac{126}{2}=63

So, Q_3=63

So, 75% of the heights of a team is less than 63 inches

Interquartile range = Q_3-Q_1=63-60=3

The interquartile range is a measure of variability on dividing a data set into quartiles.

The interquartile range is the range of the middle 50% of the terms in the data.

So, 3 is the range of the middle 50% of the heights of the students.

4 0
3 years ago
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