Answer:
Step-by-step explanation:
<u>For old circular garden:</u>
take the radius as r.
then use the formula to find area of circle: πr² ......this is old garden area.
<u>For new enlarged garden:</u>
the radius is twice the old radius so, radius = 2 * r = 2r ......enlarged radius
now find area for this new garden: π(2r)² → 4πr²
In common fractions: (old garden)/(new garden)
: ( πr² ) / ( 4πr² )
: 1/4
Answer:
The function moves 7 to the left and 5 units up
Step-by-step explanation:
y = (x + 7) + 5
I think that's the problem you put.
The given data is
t, h: 0 2 4 6 8 10
r(t), L/h: 8.6 7.9 6.8 6.4 5.7 5.3
The lower and upper estimates for the total amount that leaked may be computed as the Left and Right Riemann sums.
The shape of the graph of r versus will determine which of the two sums yields an upper or lower sum.
The plot of the graph is shown below.
The Left Riemann sum is
Sl = 2*(8.6+7.9+6.8+6.4+5.7) = 70.8 L
The Right Riemann sum is
Sr = 2*(7.9+6.8+6.4+5.7+5.3) = 64.2 L
Answer:
The lower estimate for oil leakage is 64.2 L
The upper estimate for oil leakage is 70.8 L
Answer:
Your answer is correct. The series is a geometric series with common ratio -1/4 and first term 40. So each term is:
an = 40 (-1/4)^(n−1)
So the sum of the first 10 terms is:
∑(n=1 to 10) [ 40 (-1/4)^(n−1) ]
I’m pretty sure the width would be 15 be 4 to 2 is the same as 2 to 1