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wlad13 [49]
2 years ago
14

Tomas learned that the product of the polynomials

rmula1" title="(a+b)(a^2-ab+b^2)" alt="(a+b)(a^2-ab+b^2)" align="absmiddle" class="latex-formula"> was a special pattern that would result in a sum of cubes, a^3+b^3.
His teacher put four products on the board and asked the class to identify which product would result in a sum of cubes if a=2x and b=y.
Mathematics
1 answer:
Liula [17]2 years ago
3 0

We are provided , Tomas learned <em><u>that a³ + b³ = (a + b ) ( a² - ab + b² )</u></em> , and his teacher writes four products on the board and we have to tell that which product suits the best if <em><u>a = 2x</u></em> and <em><u>b =</u></em><em><u> </u></em><em><u>y</u></em>

Now , putting a = 2x , b = y in the given formula we have :

{:\implies \quad \sf (2x)^{3}+(y)^{3}=(2x+y)\{(2x)^{2}-2\cdot x\cdot y+(y)^{2}\}}

{:\implies \quad \bf \therefore \quad \underline{\underline{(2x)^{3}+(y)^{3}=(2x+y)(4x^{2}-2xy+y^{2})}}}

Hence , The product <em>(2x+y) (4x²-</em><em>2</em><em>xy+y²)</em> would result in the sum of cubes of 2x & y :D

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Find any integer between<br>-3.92 and 12,4​
timurjin [86]

Answer:

There are 16 integers between -3.92 and 12.4

Step-by-step explanation:

If we want to find the integers between two numbers we just need to subtract the integer numbers of the interval.

The integer interval will be:

[-3,12]

Now, we subtract them:

12-(-3)=12+3=15

Let's recall that 0 is an integer

Therefore, the answer will be 16.

I hope it helps you!

8 0
2 years ago
Can someone help me on these problems and show work
Salsk061 [2.6K]

The simplified expression are as follows;

6mn³ - mn² +  3mn³ + 15mn² =  9mn³ + 14mn²

a⁴b³ + 8a⁴b³  = 9a⁴b³

<h3>How to simplify an expression?</h3>

A simplified expression is express to its lowest term.

Therefore,

6mn³ - mn² +  3mn³ + 15mn²

combine like terms

6mn³  +  3mn³ - mn² + 15mn²

9mn³ + 14mn²

a⁴b³ + 8a⁴b³  = 9a⁴b³

learn more on simplification here: brainly.com/question/403991

#SPJ1

3 0
1 year ago
The factorization of 8x3 -125 is (2x-5)(jx2 +kx+25)
lbvjy [14]

\bf ~\hspace{10em}\textit{difference and sum of cubes} \\\\ a^3+b^3 = (a+b)(a^2-ab+b^2) ~\hfill a^3-b^3 = (a-b)(a^2+ab+b^2) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ 8x^3-125~~ \begin{cases} 8=2\cdot 2\cdot 2\\ \qquad 2^3\\ 125=5\cdot 5\cdot 5\\ \qquad 5^3 \end{cases}\implies 2^3x^3-5^3\implies (2x)^3-5^3 \\[2em] [2x-5][(2x)^2+(2x)(5)+5^2]\implies (2x-5)(\stackrel{\stackrel{j}{\downarrow }}{4}x^2+\stackrel{\stackrel{k}{\downarrow }}{10}x+25)

3 0
3 years ago
How do I solve this and what is the answer
expeople1 [14]
(-3) - (-3) = - 6
3 + (-3) = 0
4 0
3 years ago
The line l passes through the point P = (1,-1,1) and has direction vector d = [2,3,1]. Determine whether l and the plane 4x-y+5z
suter [353]
Hello : 
the normal vector of the plane is : d' = [4,-1,5]...(vector  perpendicular to the plane)<span>
d </span><span>⊥ d' because : (4)(2)+(-1)(3)+(5)(1)=0
</span>the line is perpendicular to the plane .
3 0
3 years ago
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