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Vikki [24]
3 years ago
10

If θ is an angle in standard position that terminates in Quadrant IV such that cosθ = 3/5, then cosθ/2 = _____. -

Mathematics
1 answer:
Sveta_85 [38]3 years ago
4 0

Answer:

cos \frac{\theta}{2}= 0.894.

Step-by-step explanation:

Given:

cos\ \theta= \frac35

We need to find cos \ \frac{\theta}{2}

Solution:

cos\ \theta= \frac35

First we will find the value of \theta.

Now taking cos^{-1} on both side we get;

\theta= cos^{-1} \ \frac{3}{5}\\\\\theta = 53.13

Now we will find the \frac{\theta}{2}.

\frac{\theta}{2} = \frac{53.13}{2} = 26.565

Now we will find cos \ \frac{\theta}{2} we get;

cos \frac{\theta}{2}=cos\ 26.565 = 0.894

Hence cos \frac{\theta}{2}= 0.894.

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Lamar is fertilizing his garden. The garden is in the shape of a rectangle. Its length is 16 feet and its width is 13 feet. Supp
Vera_Pavlovna [14]

Answer:

8

Step-by-step explanation:

16x13=208

208÷26=8

8 bags of fertilizer

5 0
4 years ago
The given matrix is the augmented matrix for a linear system. Use technology to perform the row operations needed to transform t
shtirl [24]

Answer:

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

Step-by-step explanation:

As the given Augmented matrix is

\left[\begin{array}{ccccc}9&-2&0&-4&:8\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 1 :

r_{1}↔r_{1} - r_{2}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\8&12&-6&5&:-2\end{array}\right]

Step 2 :

r_{3}↔r_{3} - 8r_{1}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&7&-1&-1&:9\\0&124&-54&77&:-82\end{array}\right]

Step 3 :

r_{2}↔\frac{r_{2}}{7}

\left[\begin{array}{ccccc}1&-14&6&-9&:10\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&124&-54&77&:-82\end{array}\right]

Step 4 :

r_{1}↔r_{1} + 14r_{2} , r_{3}↔r_{3} - 124r_{2}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&- \frac{254}{7} &\frac{663}{7} &:-\frac{1690}{7} \end{array}\right]

Step 5 :

r_{3}↔\frac{r_{3}. 7}{254}

\left[\begin{array}{ccccc}1&0&4&-11&:-8\\0&1&-\frac{1}{7} &-\frac{1}{7} &:\frac{9}{7} \\0&0&1&-\frac{663}{254} &:-\frac{1690}{254} \end{array}\right]

Step 6 :

r_{1}↔r_{1} - 4r_{3} , r_{2}↔r_{2} + \frac{1}{7} r_{3}

\left[\begin{array}{ccccc}1&0&0&-\frac{71}{127} &:\frac{176}{127} \\0&1&0&-\frac{131}{254} &:\frac{284}{127} \\0&0&1&-\frac{663}{254} &:\frac{845}{127} \end{array}\right]

∴ we get

x_{1} = \frac{176}{127} + \frac{71}{127}x_{4}\\\\ x_{2} = \frac{284}{127} + \frac{131}{254}x_{4}\\\\x_{3} = \frac{845}{127} + \frac{663}{254}x_{4}\\

6 0
3 years ago
3X 10 multiple the number​
zysi [14]

Answer:

90

Step-by-step explanation:

3 x 10 with a tiny three

10 x tiny3 = 30

30 x normal 3 = 90

4 0
3 years ago
in the ratey the cat animation there is a guy who earns $10 per lawn complete the table below that represents money earned per l
Setler [38]

earns $10 PER lawn. Complete the table below that represents money earned PER lawn. Lawns Mowed. Money Earned. 1. 2. 3. 5. 10. 250.

7 0
3 years ago
Help with question 1 and 2 (I starred them so you know)
tigry1 [53]
I can help you only with  #2.

Area= l*w
Area=(l+3)*w
Area= 130
Let's try 10 and 13.
Is the length 3 greater than its width? YES
Does it multiply to 130? YES

LENGTH= 13 CM
WIDTH=10 CM

cHECK=
13*10=130

4 0
3 years ago
Read 2 more answers
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