$f(x)=x^6-x^5-x^4+4x^3-12x^2+12\\\\12:\{\pm1;\ \pm2;\ \pm3;\ \pm4;\ \pm6;\ \pm12\}\\1:\{\pm1\}\\\\Answer:\boxed{\{\pm1;\ \pm2;\ \pm3;\ \pm4;\ \pm6;\ \pm12\}}$

8 0

3 years ago

Need help with this

likoan [24]

Answer:

The answer is h = 2A/(b+c) .

Step-by-step explanation:

You have to move all the unrelated terms to the other side by making h the subject :

$A = \frac{1}{2} (b + c)h$

$A \div \frac{1}{2} = \frac{1}{2} (b + c)h \div \frac{1}{2}$

$2A = (b + c)h$

$2A \div (b + c) = (b + c)h \div (b + c)$

$\frac{2A}{b + c} =h$

$h = \frac{2A}{b + c}$

4 0

3 years ago

I NEED THIS QUICK!!! 20 POINTS!!!

Darya [45]

You should graduate in 2014 or 2015

4 0

3 years ago

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