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Ket [755]
4 years ago
14

Please solution this question now .thank you very much​

Mathematics
1 answer:
Tanya [424]4 years ago
3 0

Answer:

  5/2

Step-by-step explanation:

Let u = sin(t). Then this is the integral ...

  \displaystyle\int_0^{\frac{\pi}{2}}{5u}\,du=\left.\dfrac{5u^2}{2}\right|_0^{\frac{\pi}{2}}=\dfrac{5}{2}(\sin(\frac{\pi}{2})^2-\sin(0)^2)=\dfrac{5}{2}(1-0)=\boxed{\dfrac{5}{2}}

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Question 15 of 24
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Hope this helps!

Thanks!

Have a great day!

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