Question

Please solution this question now .thank you very much​

Answer 1

Answer:

  5/2

Step-by-step explanation:

Let u = sin(t). Then this is the integral ...

  $\displaystyle\int_0^{\frac{\pi}{2}}{5u}\,du=\left.\dfrac{5u^2}{2}\right|_0^{\frac{\pi}{2}}=\dfrac{5}{2}(\sin(\frac{\pi}{2})^2-\sin(0)^2)=\dfrac{5}{2}(1-0)=\boxed{\dfrac{5}{2}}$