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valentina_108 [34]
3 years ago
6

Please help me I don't understand and this is due by the end of the day. I looked up ways to do this but I just don't understand

! I really need someone's help!!
A baker bought some flour. He used 2/5 of the flour to make bread and used the rest to make batches of muffins. If he used 16 lb. of flour making bread and 2/3 lb. for each batch of muffins, how many batches of muffins did he make?
Mathematics
1 answer:
EastWind [94]3 years ago
8 0

Answer:

well you used 6.4 pounds of flour to make bread which means you have 9.6 pounds left so you could make about 14 batches

Step-by-step explanation:

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Find parametric equations for the tangent line to the curve with the given parametric equations at the specified point. x = e^−2
Mekhanik [1.2K]

Answer:

x=1

y=s

z=1

Step-by-step explanation:

(x, y, z)=(1, 0, 1)

Substitute 0 for y

y = e^{-2t} *sin 4t\\0 = e^{-2t} *sin 4t\\\\0 = e^{-2t} *(\frac{e^{4t}-e^{-4t}}{2j} )\\0 = e^{-2t} *(e^{4t}-e^{-4t} )\\0 = e^{-2t} *e^{4t}*(1-e^{-8t} )\\\\0 = e^{2t}*(1-e^{-8t} )\\\\\\Either   \\0 = e^{2t}\\t = -inf\\or\\0 = (1-e^{-8t} )\\(e^{-8t} ) = 1\\ -8t = ln(1) =0\\t=0\\\\

Confirming if t=0 satisfy the other equation

x = e^−2t cos 4t = e^−2(0)cos(4*0)

= e^(0)cos(0) = 1

z = e^−2t  = e^−2(0)  = 0

Therefore t=0 satisfies the other equation

Finding the tangent vector at t=0

\frac{dx}{dt}=-2te^{-2t} cos4t + e^{-2t}(-4sin4t)=-2(0)e^{-2(0)} cos4(0) + e^{-2(0)}(-4sin4(0))=0\\\\ \frac{dy}{dt} =-2te^{-2t} sin4t + e^{-2t}(4cos4t)=-2(0)e^{-2(0)} sin4(0)+ e^{-2(0)(4cos4(0)) }= 1\\\\\frac{dz}{dt}  = -2te^{-2t}  = -2(0)e^{-2(0)}  = 0

The vector equation of the tangent line is

(1, 0, 1) +s(0,1,0)= (1, s, 1)

The parametric equations are:

x=1

y=s

z=1

6 0
3 years ago
With which information can you construct more than one triangle?
madreJ [45]

Answer:

b & d

Step-by-step explanation:

6 0
3 years ago
Simplify and write the trig expression in terms of sin and cos
dsp73

We have:

cot(-x)cos(-x)+sin(-x)=-\frac{1}{f(x)}

Then we use trigonometric identities to change the negative sign of the trigonometric functions, so:

-sin(x)-cot(x)cos(x)=-\frac{1}{f(x)}

We clear f(x):

f(x)=\frac{1}{sin(x)+cot(x)cos(x)}=\frac{1}{sin(x)+\frac{cos(x)}{sin(x)}cos(x)}=\frac{1}{sin(x)+\frac{cos^2(x)}{sin(x)}}

we simply what we can:

f(x)=\frac{1}{\frac{sin^2(x)+cos^2(x)}{sin(x)}}=sin(x)

Thus, the correct answer is;

f(x)=sin(x)

6 0
1 year ago
Find x if segment A B is perpendicular to segment C D in the figure below.
ki77a [65]
If segment AB is perpendicular to segment CD, then a right angle (90°) is formed.


7x + 27 = 90

7x = 63

x = 9
3 0
3 years ago
Read 2 more answers
Find the orthocenter of the triangle with the given vertices: L(2, 2), M(-4, 2), N(-2, 6) a (-2, 4) b (3, -5) c (2, -4) d (-3, 5
Norma-Jean [14]

9514 1404 393

Answer:

  (a)  (-2, 4)

Step-by-step explanation:

The orthocenter is the point of concurrence of the altitudes of the triangle.

A plot of the triangle vertices shows the triangle to be acute. That means the orthocenter is inside. This eliminates choices B, C, D, which are all points outside the triangle.

__

Conveniently, side LM is horizontal. This means the orthocenter will have the x-coordinate of the vertical line through N, which is -2. Only one answer choice has an x-coordinate of -2:

  a (-2, 4)

8 0
3 years ago
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