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3 years ago

Find the slope pls thx

Mathematics

1 answer:

Lisa [10]3 years ago

7 0

The gradient formula is (y2-y1)/(x2-x1) aka rise/run, where by (x1,y1) and (x2,y2) are two points on the line.

In this case, the gradient
= -5-(-2))/(2-(-2))
= -3/4

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The volume of a cylinder whose base,area is 500sq.cm and height is 14 cm is cu.cm

Allisa [31]

<h3> $\huge\bigstar\:$ $\Huge\tt\underline\blue{ANSWER}$ </h3><h3 /><h3 /><h3>The area is 7000.</h3>

$\huge\bigstar\:$ $\Huge\tt\underline\red{EXPLAINATION}$

The base of the cylinder = 5000 sq.cm

Height = 14cm

The volume of the cylinder = 5000× 14 = 7000

<h3>HOPE IT HELPS YOU :)</h3>

6 0

4 years ago

-4(2x+5)=5(-2x-3) lhs= rhs=<br> answer pls

Mrrafil [7]

This is NOT an identity. Therefore lhs cannot equal rhs. x=5/2

7 0

3 years ago

What is the exact value of the expression √486−√24+√6? Simplify if possible.

nikitadnepr [17]

√486 - √24 + <span>√6 =
</span>√81*6 - √4*6 + <span>√6 =
</span>9√6 - 2√6 + <span>√6 =
8</span><span>√6

The correct answer is 8</span><span>√6. </span>

5 0

3 years ago

For the following telescoping series, find a formula for the nth term of the sequence of partial sums {Sn}. Then evaluate limn→[

Ivenika [448]

Answer:

The following are the solution to the given points:

Step-by-step explanation:

Given value:

$1) \sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2}\\\\2) \sum ^{\infty}_{k = 1} \frac{1}{(k+6)(k+7)}$

Solve point 1 that is $\sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2}\\\\$ :

when,

$k= 1 \to s_1 = \frac{1}{1+1} - \frac{1}{1+2}\\\\$

$= \frac{1}{2} - \frac{1}{3}\\\\$

$k= 2 \to s_2 = \frac{1}{2+1} - \frac{1}{2+2}\\\\$

$= \frac{1}{3} - \frac{1}{4}\\\\$

$k= 3 \to s_3 = \frac{1}{3+1} - \frac{1}{3+2}\\\\$

$= \frac{1}{4} - \frac{1}{5}\\\\$

$k= n^ \to s_n = \frac{1}{n+1} - \frac{1}{n+2}\\\\$

Calculate the sum $(S=s_1+s_2+s_3+......+s_n)$

$S=\frac{1}{2}-\frac{1}{3}+\frac{1}{3}-\frac{1}{4}+\frac{1}{4}-\frac{1}{5}+.....\frac{1}{n+1}-\frac{1}{n+2}\\\\$

$=\frac{1}{2}-\frac{1}{5}+\frac{1}{n+1}-\frac{1}{n+2}\\\\$

When $s_n \ \ dt_{n \to 0}$

$=\frac{1}{2}-\frac{1}{5}+\frac{1}{0+1}-\frac{1}{0+2}\\\\=\frac{1}{2}-\frac{1}{5}+\frac{1}{1}-\frac{1}{2}\\\\= 1 -\frac{1}{5}\\\\= \frac{5-1}{5}\\\\= \frac{4}{5}\\\\$

$\boxed{\text{In point 1:} \sum ^{\infty}_{k = 1} \frac{1}{k+1} - \frac{1}{k+2} =\frac{4}{5}}$

In point 2: $\sum ^{\infty}_{k = 1} \frac{1}{(k+6)(k+7)}$

when,

$k= 1 \to s_1 = \frac{1}{(1+6)(1+7)}\\\\$

$= \frac{1}{7 \times 8}\\\\= \frac{1}{56}$

$k= 2 \to s_1 = \frac{1}{(2+6)(2+7)}\\\\$

$= \frac{1}{8 \times 9}\\\\= \frac{1}{72}$

$k= 3 \to s_1 = \frac{1}{(3+6)(3+7)}\\\\$

$= \frac{1}{9 \times 10} \\\\ = \frac{1}{90}\\\\$

$k= n^ \to s_n = \frac{1}{(n+6)(n+7)}\\\\$

calculate the sum: $S= s_1+s_2+s_3+s_n\\$

$S= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{(n+6)(n+7)}\\\\$

when $s_n \ \ dt_{n \to 0}$

$S= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{(0+6)(0+7)}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}....+\frac{1}{6 \times 7}\\\\= \frac{1}{56}+\frac{1}{72}+\frac{1}{90}+\frac{1}{42}\\\\=\frac{45+35+28+60}{2520}\\\\=\frac{168}{2520}\\\\=0.066$

$\boxed{\text{In point 2:} \sum ^{\infty}_{k = 1} \frac{1}{(n+6)(n+7)} = 0.066}$

8 0

3 years ago

Nicanoa keeps the tickets from Ouzt for events he attends the Rachel baseball tickets to basketball taking his collection is 3:5

Arada [10]

Using proportions, it is found that he has 14 more basketball tickets than baseball tickets.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three. Due to this, relations between variables, either direct or inverse proportional, can be built to find the desired measures in the problem.

His proportion of baseball to basketball tickets is of 3:5. He has 21 baseball tickets, hence the amount of basketball tickets is found according to the following<em> rule of three</em>:

3/5 = 21/x

Applying cross multiplication:

3x = 105

x = 105/3

x = 35.

The difference is given by:

35 - 21 = 14.

He has 14 more basketball tickets than baseball tickets.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

8 0

2 years ago