Find the slope pls thx

Mathematics

1 answer:

Lisa [10]3 years ago

7 0

The gradient formula is (y2-y1)/(x2-x1) aka rise/run, where by (x1,y1) and (x2,y2) are two points on the line.

In this case, the gradient
= -5-(-2))/(2-(-2))
= -3/4

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Please Help!!

barxatty [35]

Answer:

Ok, the speed is 18 mph.

The angle is 293°, and we usually measure the angles from the x-axis, so we can write our coordinates of velocity as:

Vx = 18mph*cos(293°) = 7mph.

Vy = 18mph*sin(293°) = -16.6mph.

Then we can write this as a vector (Vx, Vy)

Velocity = (7mph, -16.6mph)

Now, for the position, we can integrate over time, and using that the position (0, 0) is the starting point of the ship, we have that the position vector is:

P(t) = (7mph*t, -16,6mph*t)

Where t is the number of hours after the ship leaved the port.

If t = 0 is 0:00pm, then at 3:30pm we have t = 3 hours and 30 minutes

one hour has 60 minutes, then 30 minutes is equivalent to 0.5 hours.

Then 3:30pm we have t = 3.5 houes.

Now we replace this in the position vector and the location of the ship at 3:30pm is:

P(3.5h) = (7mph*3.5h, -16.6mph*3.5h) = (24.5 mi, -58.1 mi)

Where the first component describes the displacement in the x-axis, and the second component describes the displacement in the y-axis.

6 0

3 years ago

Mr. Miller has a 20-foot ladder, which he

dimulka [17.4K]

Answer:

8 ft

Step-by-step explanation:

the ladder will make a right angle triangle with the house. The hypotenuse of the triangle is the ladder, 20 ft, and the height of the triagnle is 18 ft.

Solve for the base of the right angle triangle using pythagorean's theorem:

c=20, a=18, b=?

$b^{2}=c^{2} - a^{2}\\b^{2}=20^{2} - 18^{2}$