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2 years ago

What pH must organisms maintain

Chemistry

2 answers:

vazorg [7]2 years ago

7 0

It's different for each organ. So in the stomach its gotta be acidic and in your blood its gotta be neutral

MA_775_DIABLO [31]2 years ago

5 0

6.5-7.5 i believe was right

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Theory that the lithosphere is divided into tectonic plates that slowly move on

vitfil [10]

Pute because I’m smart and I know the right answer

5 0

3 years ago

Which metal will react spontaneously with Cu2+ (aq) at 25°C?

Gwar [14]

Answer:

Explanation:

The standard reduction potentials are

Au³⁺(aq ) + 3e⁻ ⟶ Au(s); 1.42

Hg²⁺(aq) + 2e⁻ ⟶ Hg(l); 0.85

Ag⁺(aq) + e⁻ ⟶ Ag(s); 0.80

Cu²⁺(aq) + 2e⁻ ⟶ Cu(s); 0.34

Mg2+(aq) + 2e- ⟶ Mg(s); -2.38

The more negative the standard reduction potential, the stronger the metal is as a reducing agent.

Mg is the only metal with a standard reduction potential lower than that of Cu, so

Only Mg will react spontaneously with Cu²⁺.

5 0

3 years ago

Read 2 more answers

Consider an element Z that has two naturally occuring isotopes with the following percent abundances: the isotope with a mass nu

rodikova [14]

Answer:

Z=22.70

Explanation:

It is given that,

An element Z that has two naturally occurring isotopes with the following percent abundances as follows :

The isotope with a mass number 22 is 65.0% abundant; the isotope with a mass number 24 is 35.0% abundant.

The average atomic mass for element Z is given by :

$Z=\dfrac{22\times 65+24\times 35}{100}\\\\Z=22.7$

So, the average atomic mass for element Z is 22.70.

3 0

3 years ago

What determines how ionic bonds will form?

Harrizon [31]

Answer:

I think the answer should be B. Number of valence electrons

8 0

3 years ago

The heat of vaporization of 1-pentanol is 55.5 kJ/mol, and its entropy of vaporization is 148 J/K.mol. What is the approximate b

____ [38]

Answer:

Approximately 100 °C.

Explanation:

Hello,

In this case, since the entropy of vaporization is computed in terms of the heat of vaporization and the temperature as:

$\Delta S_{vap}=\frac{\Delta H_{vap}}{T}$

We can solve for the temperature as follows:

$T=\frac{\Delta H_{vap}}{\Delta S_{vap}}$

Thus, with the proper units, we obtain:

$T=\frac{55500J/mol}{148J/(mol*K)} =375K\\\\T=102 \°C$

Hence, answer is approximately 100 °C.

Best regards.

6 0

3 years ago