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grigory [225]
4 years ago
5

Plz help idk what this is even about

Mathematics
1 answer:
AysviL [449]4 years ago
6 0

I think the answer is A.

It's probably wanting you to use pythagorean theorem.

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I want to paint all three walls of the kitchen. One was a half cylinder. I want to paint the walls only not the ceiling. The wal
bearhunter [10]

Answer:

490.9\ ft^{2}

Step-by-step explanation:

we know that

The total area is equal to

A=10(h)+2\pi r(h)+10(h)

we have

h=9\ ft

r=5.5\ ft

\pi=3.14

substitute

A=10(9)+2(3.14)(5.5)(9)+10(9)

A=490.9\ ft^{2}

5 0
3 years ago
Can someone pls help with this? i’ll give brainliest :)
raketka [301]

Answer:

D (I think)

Step-by-step explanation:

I used a right triangle calculator and that was the answer

Below is the process the calculator did, hope it helps.

c = \sqrt{a^{2} +b^{2}

\sqrt{12^{2} + 9^{2} } = 15

6 0
3 years ago
A rectangular room is 3 3 times as long as it is wide, and its perimeter is 64 64 meters. find the dimension of the room.
lora16 [44]
Perimeter = 2L + 2W    (where L = length and W = width)

And we are given that L = 3W

So substituting for L, we have the equation:-

2(3W) + 2W = 64

6W + 2W = 64

8W = 64 

W = 8  meters

So the length = 3*8  = 24 meters

Answer:- Length = 24 m and Width = 8 m.



4 0
4 years ago
A bin contains 25 light bulbs, 5 of which are in good condition and will function for at least 30 days, 10 of which are partiall
Ira Lisetskai [31]

Answer:

The probability that it will still be working after one week is \frac{1}{5}

Step-by-step explanation:

Given :

Total number of bulbs = 25

Number of bulbs which are good condition and will function for at least 30 days = 5

Number of bulbs which are partially defective and will fail in their second day of use = 10

Number of bulbs which are totally defective and will not light up = 10

To find : What is the probability that it will still be working after one week?

Solution :

First condition is a randomly chosen bulb initially lights,

i.e. Either it is in good condition and partially defective.

Second condition is it will still be working after one week,

i.e. Bulbs which are good condition and will function for at least 30 days

So, favorable outcome is 5

The probability that it will still be working after one week is given by,

\text{Probability}=\frac{\text{Favorable outcome}}{\text{Total number of outcome}}

\text{Probability}=\frac{5}{25}

\text{Probability}=\frac{1}{5}

5 0
3 years ago
When would u need an interpreter? What would that person do?
seropon [69]
If you speak a different language this person can interpret your speaking into the language understandable by the other party
6 0
3 years ago
Read 2 more answers
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