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Lilit [14]
1 year ago
13

The production floor of a manufacturing company has 73210 employees working in 2 phase. Of 22019 employees work in the first pha

se, how many of them work in the second phase ?
Mathematics
1 answer:
MissTica1 year ago
8 0

There are 51,191 employees working in the second phase

The production floor has a total number of 73210 employees that work in 2 phases

22,019 employees work in phase one

The number of employees that work in phase one can be calculated as follows

= 73,210-22019

= 51,191

Hence 51,191 employees work in the second phase

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If you flip a fair coin 7 times, what is the probability that you will get exactly 4 tails?
kherson [118]

Answer:

u should have another number in here

Step-by-step explanation:

7 0
2 years ago
The amount of workers varies inversely with the time, in days, to complete a project. Five workers can complete a certain projec
Feliz [49]

9514 1404 393

Answer:

  8

Step-by-step explanation:

The number of days has gone down by a factor of 15/24. The number of workers is inversely proportional, so must increase by a factor of 24/15 = 8/5.

  (5 workers) × (8/5) = 8 workers

8 workers are needed to complete the project in 15 days.

6 0
2 years ago
The distance between port M and port N is 162m. A ship left port M with a speed of 45 mph. In 45 minutes another ship left port
matrenka [14]

Answer:

After 900 minutes

Step-by-step explanation:

when we convert the velocities of the ships into miles/ min we get

45mph=45m/60min=0.75m/min

36mph=36m/60min=0.6m/min

The equations determining the distances  of the ships from the port M (set at x=0) are

D_1=0.75t (for 45mph ship)

D_2=162+0.6(t-45) (for 36mph ship)

The solution to these equation lie at t= 900 minutes; therefore the two ships will meet 900 minutes after the departure of the first ship.

8 0
3 years ago
Read 2 more answers
Two ships have a harbor entrance at the same time. The first ship is traveling at a constant 16 mph, while the second is traveli
stepan [7]
So hmm check the picture below

both ships leave at the same time, one is going 16mph, the other 20mph, 2hrs later on the road

at 16mph well, 2hrs is just 16+16, or 32 miles away
20mph for 2hrs, is 20+20, or 40 miles away

using the law of cosines  \bf x = \sqrt{{{ 32}}^2+{{ 40}}^2-2(32)(40)cos(169^o)}

again, recall, the angle is in degrees, so, when taking the cosine, make sure your calculator is in Degree mode

5 0
2 years ago
...........................
Nezavi [6.7K]

5\left(\dfrac{1+i}{1-i}\right)^6+6\left(\dfrac{1-i}{1+i}\right)^5=\\\\5\left(\dfrac{(1+i)^2}{1+1}\right)^6+6\left(\dfrac{(1-i)^2}{1+1}\right)^5=\\\\5\left(\dfrac{(1+i)^2}{2}\right)^6+6\left(\dfrac{(1-i)^2}{2}\right)^5=\\\\5\cdot \dfrac{(1+i)^{12}}{64}+6\cdot \dfrac{(1-i)^{10}}{32}=\\\\5\cdot \dfrac{-64}{64}+6\cdot \dfrac{-32i}{32}=\\\\-5-6i

8 0
3 years ago
Read 2 more answers
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