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shusha [124]
3 years ago
13

The dance committee of Pine Bluff Middle School earns 72$

Mathematics
1 answer:
Art [367]3 years ago
7 0

Answer: Continue... (:

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Hunter had 3⁄8 of a pizza. He gave 2⁄3 of the pizza to his friend Taylor. What fraction of the whole pizza did Taylor get?
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1/4

Step-by-step explanation:

3/8 * 2/3 = 6/24 = 1/4

AAAAAAAA  .... whole pizza

AAA  ... Hunter had

AA    ... tylor get

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Mike spent half of his allowance going to the movies. He washed the family cat and earned $7. What is his weekly allowance if he
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A random sample of 16 one-kilogram sugar packets is obtained and the actual weights of the packets are measured. The sample mean
elena55 [62]

Answer:

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

Step-by-step explanation:

We are in posession of the sample's standard deviation, so we use the student's t-distribution to find the confidence interval.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 16 - 1 = 15

99% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 35 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.99}{2} = 0.905([tex]t_{995}). So we have T = 2.9467

The margin of error is:

M = T*s = 2.9467*0.058 = 0.171

In which s is the standard deviation of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 1.053 - 0.171 = 0.882kg

The upper end of the interval is the sample mean added to M. So it is 1.053 + 0.171 = 1.224 kg.

The 99% two-sided confidence interval for the average sugar packet weight is between 0.882 kg and 1.224 kg.

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3 years ago
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