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g100num [7]
3 years ago
6

Predict how many times a consonant will not be picked?

Mathematics
1 answer:
In-s [12.5K]3 years ago
6 0

If its the entire alphabet then the answer is 5/26

You might be interested in
Geometry math question
lawyer [7]

Supplementary angles add up to 180

so (2x + 3) + (3x + 2) = 180

.

<u>Solve x:</u>

2x + 3 + 3x + 2 = 180

5x + 5 = 180

5x = 175

x = 35

.

<u>Find the angles:</u>

One angle = (2x + 3) = 2(35) + 3 = 73°

Other angle = (3x + 2) = 3(35) + 2 = 107°

.

Answer: The two angles are 73° and 107°

4 0
3 years ago
Read 2 more answers
Help me please i have been stuck on this
Sveta_85 [38]

Answer:

3 1/8

Step-by-step explanation:

You can rewrite 1 1/4 as 1 2/8, so adding them you'd get 2 9/8, or 3 1/8

3 0
3 years ago
Please answer this question i need it today please I really need help
kumpel [21]

Answer:

4) D

200+180+360= 740

20) C

21) B

55*2+75*2

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
What is relationship between the circumference and the diameter
Mkey [24]

Answer & Step-by-step explanation:

The circumference is basically the perimeter of a circle. The circumference of a circle is found by multiplying the diameter by π (pi):

C=\pi d

or by multiplying the radius (which is half of the diameter) by 2 and π:

C=2\pi r

7 0
3 years ago
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Once a fire is reported to a fire insurance company, the company makes an initial estimate, X, of the amount it will pay to the
Olenka [21]

Answer:

The probability that the final settlement amount is between 1 and 3 given that the initial claim is 2 = (2/9) = 0.2222

Step-by-step explanation:

The complete question is presented in the attached image to this solution

The joint probability distribution is given as

f(x, y) = {2/[x²(x - 1)} × y^-[(2x-1)/(x-1)] for x>1 And y>1

Given that the initial claim estiamted by the comapny is 2, determine the probability that the final settlement amount is between 1 and 3.

That is, x = 2, and y ranges from 1 to 3

Inserting x = 2 into the expression, we obtain

f(y) = (1/2) × y⁻³ = (y⁻³/2)

The required probability would then be

P(1 < y ≤ 3) = ∫³₁ f(y) dy

= ∫³₁ (y⁻³/2) dy

= [y⁻²/-4]³₁

= [3⁻²/-4] - [1⁻²/-4]

= (-1/36) - (-1/4)

= (1/4) - (1/36)

= (8/36)

= (2/9) = 0.2222

Hope this Helps!!!

4 0
4 years ago
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