Answer:
the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)
= -5 = -2x + 15
Step-by-step explanation:
Write an equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5).
Using the slope intercept equation,
y = mx +c
m = slope = 1/2
For two lines to be perpendicular, the product of their slopes is -1
Let the slope of the other line be m2
m1×m2 =-1
1/2×m2 = -1
m2 = -1/(1/2) = -2
Slope of line = -2
For points (10, -5), x = 10, y =-5
-5 = -2× 10 +c
-5 = -20+ c
c = -5+20= 15
the equation of the line that is perpendicular to y = 1/2x + 3 and passes through the point (10, -5)
-5 = -2x + 15
Answer:
√(137)
Step-by-step explanation:
First, you will need to find the other side length.....then you can use the Pythagorean Theorem to find the diagonal:
L x W = 44
4 x W = 44
W =11
Now the Pythag, Theorem:
diagonal^2 = 4^2 + 11^2
d^2 = 16+121
d^2 = 137
d = √(137)
Answer:
The required equation is: 
Step-by-step explanation:
We need to find equation from the table given
x f(x)
3 -5
7 -2
11 1
15 4
We can write equation in the form of 
where m is slope and b is y-intercept.
Finding Slope
We can used the slope formula to find slope: 
From the table we have: 
Putting values and finding slope

So, we get slope 
Now, finding y-intercept
Using the slope
and point (3,-5) we can find y-intercept

The y-intercept is 
So, the equation having slope
and y-intercept
will be:

The required equation is: 