Question

What is the equation of the line perpendicular to 2x+y=0 that passes through the point (2,2)

Answer 1

2x + y = 0
y = -2x.....the slope here is -2. A perpendicular line will have a negative reciprocal slope. To find the negative reciprocal slope, flip the original slope and change the sign. So we have slope -2 or -2/1.....flip it and it becomes -1/2....change the sign and it becomes 1/2. So ur perpendicular line will have a slope of 1/2.

y = mx + b
slope(m) = 1/2
(2,2)....x = 2 and y = 2
now sub and find b, the y int
2 = 1/2(2) + b
2 = 1 + b
2 - 1 = b
1 = b
so ur perpendicular equation is : y = 1/2x + 1 <===