You can not use either of them because neither of them have a variable= to the eqaution
ex.) y= 3x+25
Answer:
y= 6/5x + 2
If you substitute the points (5,8) you get:
8 = 6/5 × 5 + 2
8 = 6 + 2
Step-by-step explanation:
1. Let's call:
x: the width of the walkway.
b: 2x+16 (there is a widht "x" of the walkway on each side).
h: 2x+32 (there is a widht "x" of the walkway on each side).
A: 924 ft^2 ( the area of the pool of including the walkway).
2. The area of a rectangle is:
A=(b)(h)
b: the base of the rectangle (2x+16)
a: the height of the rectangle (2x+32)
3. Then, we have a quadratic equation:
924=(2x+16)(2x+32)
4x^2+64x+32x+512-924=0
4x^2+96x-412=0
4. We apply the quadratic formula to find the value of "x":
x=(-b±√(b^2-4ac))/2a
x=3.71
The answer is: The width of the walkway is 3.71 ft
Answer:
1253 inches cubed
Step-by-step explanation:
V=L*W*H,so 11*14*7=1078 and 7*5*5=175
175+1078=1253
Mark me brainliest if I helped:D
