Convert: 70 mm = _____ m

Mathematics

2 answers:

GaryK [48]4 years ago

8 0

Correct answer is
0.07 m

Sedbober [7]4 years ago

7 0

If you're talking about converting 70 millimeters in to meters the answer is 0.07 meters<span />

You might be interested in

naughty spent $28 on 2 DVDs at this rate how much would five DVDs cost and what rate did she spend her money

ioda

If you divided 28 by 2 you will get 14 then times that by 5 and you will get 70 that is how much 5 will be

5 0

4 years ago

Write a slope intercept equation for a line passing through the point (4,-2) that is parallel to the line 4x+5y=7. Then write a

LuckyWell [14K]

First, the equation needs to be put into slope-intercept form, which is y = -4/5x + 7/5. Then, you need to know what parallel and perpendicular lines are. REMEBER, parallel lines have the same slope, and perpendicular lines have slopes whose product equal -1. You just need to substitute. For the parallel line, -2 = -4/5(4) + b, and b = 6/5, so y = -4/5x + 6/5. For the perpendicular line, the slope is 5/4. Now substitute. -2 = 5/4(4) + b, and b = -7, so y = 5/4x -7.

3 0

4 years ago

A new pair of basketball shoes costs $98.00 at the sporting goods store. If there is a 10% sales tax, what is the actual cost of

tiny-mole [99]

107.80$ is the actual cost of the shoes

5 0

3 years ago

Read 2 more answers

Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

$Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}$

$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$

6 0

3 years ago

Read 2 more answers

Write an equation in slope intercept form for the line that satisfies each set of conditions. Has y intercept -2 , parallel to t

Gwar [14]

Y = 2x - 2

is the parallel line has a slip of 2 then your line has a slip of 2.

3 0

3 years ago