Question

3(2^x) = 6^2x How do you solve this?

Answer 1

$3(2^x)=6^{2x}$
$3(2^x)=(3\times2)^{2x}$
$3(2^x)=3^{2x}2^{2x}$
$\ln(3(2^x))=\ln(3^{2x}2^{2x})$
$\ln3+\ln2^x=\ln3^{2x}+\ln2^{2x}$
$\ln3+x\ln2=2x\ln3+2x\ln2$
$\ln3=2x\ln3+2x\ln2-x\ln2$
$\ln3=x(2\ln3+\ln2)$
$x=\dfrac{\ln3}{2\ln3+\ln2}$