Answer:
2 km
Step-by-step explanation:
Since we know that the TOTAL distance from Kensington to Greenville is 4.3 km, and we also that the distance from Kensington to Springfield is 2.3 km, we can subtract these values to find the distance from Springfield to Greenville.

I hope this helped!
If it reaches its maximum height a t=3 its velocity must be zero at t=3
dy/dx=0 at t=3
dA/dx=4x+12=24 at t=3 so this does not apply
dB/dx=-4x+12=0 at t=3 and B=13 at t=3 so B applies
dC/dx=-4x-12=-24 at t=3 so this does not apply
dD/dx=-4x-12=-24 at t=3 so this does not apply
dE/dx=-4x-12=-24 at t=3 so this does not apply
So only quadratic B: reaches a maximum height of 13 feet at 3 seconds.
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Answer:
3 3/8 seconds.
Step-by-step explanation:
When it reaches the ground h = 0 so:
54t - 16t^2 = 0
16t^2 - 54t = 0
2t(8t - 27) = 0
t = 0 or t = 27/8 (we ignore the t = 0 ) so:
t = 3 3/8 seconds.