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Dmitrij [34]
4 years ago
7

A pump installed on a wall can pump at a maximum rate of 100 gallons per minute. If the pump runs at 50% of its maximum rate for

six hours a day, how much water is pumped in one day?
A. 3.00 x 10^2 gallons
B. 1.80 x 10^4 gallons
C. 3.60 x 10^4 gallons
D. 7.20 x 10^4 gallons
Mathematics
1 answer:
beks73 [17]4 years ago
3 0
(50/100)(100gal/min)(60min/hr)(6hr)=18000=1.80X10^4
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Fantom [35]

Answer:

b

Step-by-step explanation:

$25 per day

it's "b" because as days increase the cost of dollars gets added by $25 per day.

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6 0
3 years ago
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tangare [24]

Answer:

d

Step-by-step explanation:

4 0
3 years ago
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(2x+3)²=5.find the roots of the equation ​
bija089 [108]

Answer:

-2.61803398875, -0.38196601125

or

(-3±√5)/2

Step-by-step explanation:

First, expand. (2x+3)² = 4x²+12x+9=5

4x²+12x+4 = 0

Quadratic equations take the form ax²+bx+c = 0

In this case,

a = 4

b = 12

c = 4

You can solve with the equation x=(-b±√b²-4ac)/2a

Plug in:

(-12±√144-64)/8

(-12±√80)/8

(-12±√2^4×5)/8

(-12±4√5)/8

(-3±√5)/2

Final answer x = (-3±√5)/2

If you want decimal form: -2.61803398875, -0.38196601125

4 0
2 years ago
Find a better estimate of √2.
Goryan [66]
Answer = 1.414
I used the prime factorization method.
Hope this answers your question.
4 0
2 years ago
A 27 1⁄2-mile stretch of road needs repaving. A company bid on the repaving project, saying they would repave 2 1⁄4 miles of roa
Umnica [9.8K]

Answer:

The correct answer is 12 and a half or 13 weeks.

Step-by-step explanation:

First, convert the values to decimals.

27 1/2 = 27.5

2 1/4 = 2.25

Then, divide miles of road that need to be repaved by the number of miles that are repaved per week.

27.5/2.25 = 12.2222222222222

Round that up to 12 and a half weeks or 13 weeks.

8 0
3 years ago
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