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Yuki888 [10]
3 years ago
13

Graph the function f(x)=1.5x^2 and identify domain and range

Mathematics
1 answer:
seraphim [82]3 years ago
8 0
Given:
f(x) = 1.5x²

Domain is all the values of x. 
Range is all the values of y.

x    y
1   f(1) = 1.5(1²) = 1.5(1) = 1.5
2   f(2) = 1.5(2²) = 1.5(4) = 6
3   f(3) = 1.5(3²) = 1.5(9) = 13.5
4   f(4) = 1.5(4²) = 1.5(16) = 24
5   f(5) = 1.5(5²) = 1.5(25) = 37.5

If we graph it, the following coordinates will be:
1st point (1,1.5)
2nd point (2,6)
3rd point (3,13.5)
4th point (4,24)
5th point (5,37.5)
so on...
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3 years ago
(4x+___)+(2x+3)=6x+5<br> Find the missing term.
SOVA2 [1]

Answer:

(4x+2)+(2x+3)=6x+5

Step-by-step explanation:

(4x+___)+(2x+3)=6x+5

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10 to the power of 2 divided by 4 divided by 3 plus 2
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Write the quadratic equation that has roots -1-rt2/3 and -1+rt2/3 if its coefficient with x^2 is equal to 1
weeeeeb [17]

The equation of the quadratic function is f(x) = x²+ 2/3x - 1/9

<h3>How to determine the quadratic equation?</h3>

From the question, the given parameters are:

Roots = (-1 - √2)/3 and (-1 + √2)/3

The quadratic equation is then calculated as

f(x) = The products of (x - roots)

Substitute the known values in the above equation

So, we have the following equation

f(x) = (x - \frac{-1-\sqrt{2}}{3})(x - \frac{-1+\sqrt{2}}{3})

This gives

f(x) = (x + \frac{1+\sqrt{2}}{3})(x + \frac{1-\sqrt{2}}{3})

Evaluate the products

f(x) = (x^2 + \frac{1+\sqrt{2}}{3}x + \frac{1-\sqrt{2}}{3}x + (\frac{1-\sqrt{2}}{3})(\frac{1+\sqrt{2}}{3})

Evaluate the like terms

f(x) = x^2 + \frac{2}{3}x - \frac{1}{9}

So, we have

f(x) = x²+ 2/3x - 1/9

Read more about quadratic equations at

brainly.com/question/1214333

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7 0
2 years ago
Ellema knows that 1/5 written as a decimal is 0.2. How can Ellema use this information to find the decimal equivalent for 9/5 wi
Rus_ich [418]

Answer:

1.8

Step-by-step explanation:

0.2 times 5 is 1.8

3 0
3 years ago
Read 2 more answers
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