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jok3333 [9.3K]
3 years ago
9

What is the percent change if the student population of the school goes from 380 students to 335 students? Round to the nearest

whole percent.
12% decrease


25% increase


12% increase


45% decrease
Mathematics
2 answers:
lys-0071 [83]3 years ago
6 0

Answer:

12% decrease

Step-by-step explanation:

I'm srry if I'm wrong but I'm 90-ish% its correct

Lelechka [254]3 years ago
5 0

Answer:

45% decrease

Step-by-step explanation:

Percent change formula

To calculate percent change we need to take the difference between the starting value and final value, divide by the absolute value of the starting value, and multiply the result by 100.

380/335

1.13x100

113-335-380

158

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Given that a 90% confidence interval for the mean height of all adult males in Idaho measured in inches was [62.532, 76.478]. Us
grigory [225]

Answer:

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

Step-by-step explanation:

Previous concepts

The margin of error is the range of values below and above the sample statistic in a confidence interval.  

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

\bar X represent the sample mean  

\mu population mean (variable of interest)  

\sigma represent the population standard deviation  

n represent the sample size  

Assuming the X follows a normal distribution  

X \sim N(\mu, \sigma)

The confidence interval on this case is given by:

\bar X \pm z_{\alpha/2}\frac{\sigma}{\sqrt{n}} (1)

For this case the confidence interval is given by (62.532, 76.478)[/tex]

And we can calculate the mean with this:

\bar X = \frac{62.532+76.478}{2}= 69.505

So then the mean for this case is 69.505

5 0
3 years ago
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bija089 [108]

Answer:

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Step-by-step explanation:5.5+6=11.5

5 0
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konstantin123 [22]

Answer:

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hope it helps...

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6 0
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Answer:

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