Option C:
x = 90°
Solution:
Given equation:

<u>To find the degree:</u>

Subtract 1 + cos²x from both sides.

Using the trigonometric identity:




Let sin x = u

Factor the quadratic equation.

u + 2 = 0, u – 1 = 0
u = –2, u = 1
That is sin x = –2, sin x = 1
sin x can't be smaller than –1 for real solutions. So ignore sin x = –2.
sin x = 1
The value of sin is 1 for 90°.
x = 90°.
Option C is the correct answer.
Given
x^5*k=a .................(1)
x^2*k=b .................(2)
We need to find x^3.
Solution:
On inspection, we note that (1)/(2) gives x^3 on the left hand side, but the division is valid on conditions that x ≠ 0 and k ≠ 0.
So we conclude:
(1) / (2)

=>

=>
on condition that
and
Answer:
x(t) = 37cos(70o)t and y(t) = –16t2 + 37sin(70o)t
Step-by-step explanation:
Answer:
3
4
7
9
12
<em>Hope that helps!</em>
<em>-Sabrina</em>
Step-by-step explanation: