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11Alexandr11 [23.1K]
3 years ago
8

Formula for the area of parallelogram is _______.

Mathematics
1 answer:
taurus [48]3 years ago
5 0

Step-by-step explanation:

Area = Base  \times Height

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Using the distance formula, d = √(x2 - x1)2 + (y2 - y1)2, what is the distance between point (0, 5) and point (3, -1) rounded to
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\sqrt{(3-0)^2+(-1-5)^2}=\sqrt{3^2+(-6)^2}=\sqrt{45}\approx 6.7

answer (a)

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4 years ago
What’s the difference between x and 4 is greater than 10
daser333 [38]

Answer:

There is a whole range of speeds at which you are allowed to drive, not just one. In cases like this where there is more than one correct answer, we use inequalities, not equations, to represent the situation.

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6 0
3 years ago
In each part (a)-(d) below, some additional assumptions about the
Viktor [21]

In the triangle, the fact that wee are given 2AX = 3XD isn't enough to prove similarity.

<h3>How to explain the triangle?</h3>

a. In the question, we are given 2AX = 3XD. An arbitrary triangle AXB can be drawn where one extends AX and choose a point D on the extended line in order for 2AX = 3XD. Also, extend BX and choose a point C on the line so that 2BX = XC. Even though they both satisfy the condition, they're not similar.

b. We are given that AX/BX = DX/CX. When this is rearranged, we'll have AX/DX = BX/CX. In this case, let AX/DX = k. DX and AX will align upon rotation of 180°. The triangle can then be dilated by a factor of k. This brings about the mapping of triangle DXC to AXB. Therefore, the original triangle DXC is similar to AXB.

c. Lines AB and CD are parallel. Here, the dilation moves line CD onto line AB. Here, since the dilation moves D to a point on ray XA, D must move to A. Therefore, the rotation of triangle DXC is similar to AXB. Therefore, DXC is similar to AXB.

d. Here, angle XAB is congruent to angle XCD. This shows similarity and in this case, XCD is similar to XAB.

Learn more about triangles on:

brainly.com/question/28021872

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4 0
2 years ago
the music hall has 20 boxes on thurs 2/5 were occupied, on friday 2/4 were occupied and o saturday 8/10 were occupied. Using sym
NikAS [45]
<span><span>1.       </span>The music hall has 20 boxes :
=> on thurs 2/5 were occupied
=> on friday 2/4 were occupied
=> and on saturday 8/10 were occupied.
Let’s find out which day has the most occupied space of the music hall.
2/5 + 2/4 + 8/10 = 6/20 + 7/20 + 10/20
Thurs 2/5 were occupied
=> 6/20 = 0.3
=> 20 * 0.3 = 6 boxes
Friday 2/4 were occupied
=> 7/20 = 0.35
=> 20 * 0.35 = 7 boxes
Saturday 8/10 were occupied.
=> 10/20 = 0.5
=> 20 * .5 = 10 boxes
Thus, during Saturday has the most number of occupied boxes.</span>



8 0
3 years ago
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