Answer:
a) 6 gigabytes
b) $100
Step-by-step explanation:
Let c represent the total cost in dollars and d represent the amount of data used in gigabytes.
For the first smartphone
One smartphone plan costs $52 per month for talk and messaging and $8 per gigabyte of data used each month.
Equation =
c = 52 + 8d
For the Second smartphone
A second smartphone plan costs $82 per month for talk and messaging and $3 per gigabyte of data used each month.
Equation =>
c = 82 + 3d
How many gigabytes would have to be used for the plans to cost the same?
We would equate both cost to each other
52 + 8d = 82 + 3d
Collect like terms
8d - 3d = 82 - 52
5d = 30
d = 30/5
d = 6
Therefore,
a) The number of gigabytes for the cost of both Smartphone data plans to be the same = 6 gigabytes.
b) The cost of both plans if 6 gigabytes is used =>
c = 52 + 8d
c = 52 + 8 × 6
c = $100
Weight of an grapefruit=weight of an orange+8% weight of an orange
weight of an apple=weight of an orange -10% weight of an orange
a.<span>By what percentage is the grapefruit heavier than the apple?
We should find the connection between grapefruit and an apple. We know the connection between the weight of a grapefruit and an orange, we know the connection between an orange and an apple, so this means we know the connection between a grapefruit and an apple.
</span>
weight of an grapefruit=weight of an <span>orange+8% weight of an orange
</span>weight of an orange=weight of an apple<span> +10% weight of an apple
</span>
-> weight of an grapefruit=weight of an apple+10% weight of an apple + 8%(weight of an apple+10% weight of an apple)= weight of an apple + 18% weight of an apple + 2% weight of an apple= <span>weight of an apple + 20% weight of an apple
</span><span>b.By what percentage is the apple lighter than the grapefruit?
</span>weight of an grapefruit=weight of an apple + 20% weight of an apple<span>
</span>
-> The apple ts 20% lighter than the grapefruit.
In the third equation, the left side has ab.
You are solving for a, so you need a alone.
Dividing ab by b gives you a alone.
Answer: The third choice.
1.<AFC
2.<AFD
3.<AFE
4.<AFB
#5, 6 and 7
m<BAE = 59
m<BAC + m<CAD + m<DAE = m<BAE
4x - 20 + x + 12 + x + 1 = 59
6x - 7 = 59
6x = 59 + 7
6x = 66
x = 11
m<BAC = 4x - 20 = 4(11) - 20 = 24
m<CAD = x + 12 = 11 + 12 = 23
m<BAE = x + 1 = 11 + 1 = 12
answer
5.
m<BAC = 24
6.
m<CAD = 23
7.
m<BAE = 12
#8, 9 and 10
m<BAE = 130
m<BAC + m<CAD + m<DAE = m<BAE
3x - 10 + 2x + 5 + x + 15 = 130
6x + 10 = 130
6x = 120
x = 20
m<BAC = 3x - 10 = 3(20) - 10 = 60 -10 = 50
m<CAD = 2x + 5 = 2(20) + 5 = 40 + 5 = 45
m<DAE = x + 5 = 20 + 15 = 35
answer
8.
m<BAC = 50
9.
m<CAD = 45
10.
m<DAE = 35
