Answer:
60 seconds, 7715 feet
Step-by-step explanation:
Plane A and B start out 615 feet apart, and we find this by subtracting the height of plane A from plane B, getting 5000-4385=615. Now we have to find how many more feet of altitude plane A is gaining per second over plane B.
To find this we subtract 45.25 from 55.5 and get 10.25 feet per second. Now to find out how many seconds until they'll be at the same altitude we simply divide 615 by 10.25, getting 60 seconds.
For the second part, to find the altitude at this point, we simply multiply the altitude gain of one of the planes per second by the time of 60 seconds to get how much altitude they gained over that time, and add it to the starting altitude. Doing this with plane B we get 45.25*60=2715, and we add that to 5000 to get the final answer of 7715.
1) 1
2) PA: between 2 and 3.
2) PB: Unsure about it.
Answer:
3 seconds
Step-by-step explanation:
You want to set h(t)=3, then take the root such that t≠0. You would have:
3=3+48t−16t^2
Let's solve your equation step-by-step.
3=3+48t−16t2
Step 1: Simplify both sides of the equation.
3=−16t2+48t+3
Step 2: Subtract -16t^2+48t+3 from both sides.
3−(−16t2+48t+3)=−16t2+48t+3−(−16t2+48t+3)
16t2−48t=0
Step 3: Factor left side of equation.
16t(t−3)=0
Step 4: Set factors equal to 0.
16t=0 or t−3=0
t=0 or t=3
3 makes more sense than 0 because the ball can't have been in the air for 0 seconds.
So the ball was in the air for 3 seconds.
You would say it as 9 tenths
