Answer:
area of the square pyramid = a2+ 2al (or) a2+2a √a24+h2 a 2 4 + h 2 .
Step-by-step explanation:
The surface area of a square pyramid is the sum of the areas of all its 4 triangular side faces with the base area of the square pyramid. If a, h, and l are the base length, the height of the pyramid, and slant height respectively, then the surface area of the square pyramid = a2+ 2al (or) a2+2a √a24+h2 a 2 4 + h 2 .
Answer:
9.7
Step-by-step explanation:
tan=opposite/adjacent
tan=9/adjacent
tan 43=9/x
x tan 43=9
0.9325x=9
0.9325x/0.9325=9/0.9325
=9.65
hence;
x=9.7
1/3= 2/6
therefore 2/6+2/6+1/6= 5/6
To solve, you can undo the addition of -7, then undo the multiplication by -2.
... -2v = -16 . . . . . add 7
... v = 8 . . . . . . . . .divide by -2
The appropriate choice is
... 8