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3 years ago

16x^2-12x=54. Find the real solutions.

Mathematics

1 answer:

ELEN [110]3 years ago

5 0

Yes just do that.................... ....m

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Line one has the equation 7x - 4y = - 28 and line two

Pie

7x - 4y = -28

3x +4y = -12

Using the elimination method because y is already eliminated

10x = -40

So x = -4

Then plug the -4 into the first equation....

7(-4) - 4y = -28

-28 - 4y = -28

-4y = 0

y = 0

I got: -4,0

4 0

3 years ago

Find the product of 20x9x5. Tell which property is used.

Likurg_2 [28]

The answer is 900 because 20×9=180 and just multiply 180×5 and that equals 900.

8 0

3 years ago

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Debra pumped 2 gallons of water into her pool each minute for 10 minutes. Whag was ths total change in the amount of water in th

FinnZ [79.3K]

20 gallons of water in the pool

8 0

3 years ago

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Need help on probability. Please explain how you did it so I can know how to do it.

Galina-37 [17]

Answer:

$\text{P}(B \text{ or }C)=\dfrac{5}{6}$

Step-by-step explanation:

Mutually Exclusive Events

For two events, A and B, where A and B are mutually exclusive:

$\boxed{\text{P}(A \text{ or }B)=\text{P}(A)+\text{P}(B)}$

Probability distribution table:

$\begin{array}{|c|c|c|c|c|c|c|c|}\cline{1-7} x & 1 & 2 & 3 & 4 & 5 & 6 \\\cline{1-7} \text{P}(X=x)\phantom{\dfrac11}&\frac{1}{6}&\frac{1}{6}&\frac{1}{6}&\frac{1}{6}&\frac{1}{6}&\frac{1}{6}\\\cline{1-7}\end{array}$

where X is the score on a fair, six-sided dice.

P(B or C) means "the probability of rolling an even number or a multiple of 3".

As an even number of a fair, six-sided dice can never be a multiple of 3, the two events B and C are mutually exclusive.

Calculate the probabilities for events B and C.

Event B

Rolling an even number.

$\begin{aligned}\implies \text{P}(X \text{ is even})&=\text{P}(2 \text{ or }4\text{ or }6)\\\\&=\text{P}(X=2)+\text{P}(X=4)+\text{P}(X=6)\\\\& = \dfrac{1}{6}+ \dfrac{1}{6}+ \dfrac{1}{6}\\\\&=\dfrac{3}{6}\end{aligned}$

Event C

Rolling a multiple of 3.

$\begin{aligned}\implies \text{P}(X \text{ is multiple of 3})&=\text{P}(3 \text{ or }6)\\\\&=\text{P}(X=3)+\text{P}(X=6)\\\\& = \dfrac{1}{6}+ \dfrac{1}{6}\\\\&=\dfrac{2}{6}\end{aligned}$

Solution

$\begin{aligned}\implies \text{P}(B \text{ or }C)&=\text{P}(B)+\text{P}(C)\\\\& = \dfrac{3}{6}+\dfrac{2}{6}\\\\& = \dfrac{5}{6}\end{aligned}$

6 0

1 year ago

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Sarah invested $125. She earned a simple interest of 2.5% on the

kykrilka [37]

Answer:

I(Interest) = $6.25

Step-by-step explanation:

The formula for Simple Interest

A = P(1 + rt)

Where

A = Amount after t years

P = Principal, initial amount invested = $125

r = Interest rate = 2.5%

t = time in years = 2 years

Step I

We the interest rate to a decimal

r = R/100 = 2.5%/100 = 0.025 per year.

Step 2

A = 125(1 + (0.025 × 2))

A = $131.25

The Amount received after 2 years = $131.25

The amount of interest Sarah received after 2 years

I = A - P

I = $131.25 - $125

I = $6.25

5 0

3 years ago