Question

Factor the trinomial x^2 - 8x + 16

Answer 1

Hey there mate!

Your answer: $\boxed{(x-4)^2}$

$Factoring : x^2-8x+16 \\ \\ \\ \left[\begin{array}{ccc} -16 + -1 = -17 \\ \\ -8 + -2 = -10 \\ \\ -4 + -4 = -8\end{array}\right] (That's \ it!) \\ \\ \\ Add \ up \ the \first \ 2 \ terms, \ pulling \ out \ like \ factors : \\ \\ x * (x-4) \\ \\ Add \ up \ the \ last \ 2 \ terms, \ pulling \ out \ common \ factors : \\ \\ 4 * (x-4) \\ \\ Multiply \\ \\ \boxed{(x-4) by (x-4) }$

$Your \ correct \ correct \ answer \ would \ be... \\ \boxed{\boxed{(x-4)^2}}$

I hope this helps you!