All categories

3 years ago

WILL GIVE BRAINLESTthis table represents a quadratic function.....

Mathematics

1 answer:

KatRina [158]3 years ago

5 0

Everything on the y-axis side is being added by odd numbers. Ex:(1,3,5,7,9, etc).

You might be interested in

PLEASE HELP<br> Find the length of the missing side.

BabaBlast [244]

Answer:

use Pythagoras theorem

the missing side is base

Step-by-step explanation:

pythagoras theorem

h^2 = p^2 + b^2

73^2 = 48^2 + b^2

5329 = 2304 + b^2

5329 - 2304 = b^2

3025 = b^2

√3025 = b

55 = b

3 0

3 years ago

Suppose that the path of a newly discovered comet could be modeled by using one branch of the equation x2/4 - y2/9=1, where dist

Setler79 [48]

Answer:

the answer is A just tool the quiz lesson 5 hyperbolas Algebra 2B unit 5 these are the correct answers

1.A

2.B

3.D

4.A

5.B

6.D

7.A

hopes this helps everyone

6 0

3 years ago

Read 2 more answers

You purchase a car worth $25077 and make a down payment of $3560. You intend to repay the balance of the car with month end car

zubka84 [21]

Answer:

value of buyout is $4185.74

Step-by-step explanation:

given data

car worth = $25077

down payment = $3560

monthly payment = $336 = 336 × 6 = $2016 per semi annually

time = 5 year = 10 half yearly

rate = 4.04 %

to find out

value of final buyout

solution

we know here loan amount will be 25077 - 3560 = $21517

and we find present value first by formula that is

present value = $\frac{amount(1+r)^t - 1}{r (1+r)^t}$

put here t = 10 and r = $\frac{4.04}{200}$

present value = $\frac{2016(1+\frac{4.04}{200})^10 - 1}{r (1+\frac{4.04}{200})^10}$

present value = 18089.96

loan unpaid amount is here

loan unpaid amount = 21517 - 18089.96

loan unpaid amount = $3427.04

now we calculate value of buyout

that is express as

amount = principal × $(1+r)^{t}$

amount = 3427.04 × $(1+\frac{4.04}{200})^{10}$

amount = 4185.74

so value of buyout is $4185.74

7 0

4 years ago

Which of the following is equal to the expression above

EleoNora [17]

Answer:

$15 \sqrt[3]{2}$

Step-by-step explanation:

${(27 \times 250)}^{ \frac{1}{3} } = {(27 \times 125 \times 2)}^{ \frac{1}{3} } \\ = {27}^{ \frac{1}{3} } \times {125}^{ \frac{1}{3} } \times {2}^{ \frac{1}{3} } \\ = \sqrt[ 3]{27} \times \sqrt[3]{125} \times \sqrt[3]{2} \\ = \sqrt[3]{ {3}^{3} } \times \sqrt[3]{ {5}^{3} } \times \sqrt[3]{2} \\ = 3 \times 5 \times \sqrt[3]{2} \\ = 15 \sqrt[3]{2}$