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ExtremeBDS [4]
3 years ago
12

WILL GIVE BRAINLESTthis table represents a quadratic function.....

Mathematics
1 answer:
KatRina [158]3 years ago
5 0
Everything on the y-axis side is being added by odd numbers. Ex:(1,3,5,7,9, etc).
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in a shop,there was a total of 93 bicycles and tricycles ,.Each bicycle had 2 wheels and each tricycles had 3 wheels .There were
liraira [26]

Answer:

68 bicycles.

Step-by-step explanation:

Let there be x bicycles, then there are (93 - x) tricycles.

From the given values:

2x + 3(93 - x) = 211

2x + 279 - 3x = 211

-x = 211 - 279 = -68

x = -68/-1 = 68.

7 0
3 years ago
Read 2 more answers
A random variable X has a mean of 10 and a standard deviation of 3. If 2 is added to each value of X, what will the new mean and
dlinn [17]

Answer:

New mean will be 12

And no change in standard deviation

Step-by-step explanation:

We know the relationship between the two mean and standard deviation

\sigma=\frac{\sqrt{x-x_i}}^2{n}

\sigma=\text{standard deviation},x=mean,n=\text{number of observations}

If we add 2 to each value of x that means the mean will become n will become 2n and since we are adding 2 to each value

The new mean will become 12

And there will be no change in the standard deviation because of equal change in the each data.

6 0
3 years ago
Show the zero property of multiplication using the number 25
9966 [12]
Anything divided by 0 is 0 for example 25x0=0 12020202020x0=0
6 0
3 years ago
Can please cross multiply this for me :)
Alchen [17]
64 x 100 = 6400
11 x x = 11x
I’ll solve this out for you
11x = 6400
Divide 11 from both sides
x = 581.8
Hope this helps!
4 0
4 years ago
Read 2 more answers
A metallurgist has an alloy with 5
alexira [117]
\bf \begin{array}{lccclll}
&amount&concentration&
\begin{array}{llll}
concentrated\\
amount
\end{array}\\
&-----&-------&-------\\
\textit{5\% alloy}&x&0.05&0.05x\\
\textit{30\% alloy}&y&0.30&0.30y\\
-----&-----&-------&-------\\
mixture&100&0.15&(100)(0.15)
\end{array}

so hmm notice, we use the decimal format for the percent, namely 15% is just 15/100 and 5% is just 5/100 and so on

whatever the amounts of "x" and "y" are, they must add up to 100 grams
thus x + y = 100

and whatever the concentrated amounts are, they'll add up to (100)(0.15)

thus     \bf \begin{cases}
x+y=100\implies \boxed{y}=100-x\\
0.05x+0.30y=(100)(0.15)\\
----------\\
0.05x+0.30\left( \boxed{100-x} \right)=(100)(0.15)
\end{cases}

solve for "x", to see how much 5% alloy will be needed

what about "y"?  well y = 100 -x
4 0
4 years ago
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