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3 years ago

Gimme some good memes, the best get Brainliest!

Mathematics

2 answers:

jeyben [28]3 years ago

4 0

Roses are Red

Violets are blue

God made me bootiful

What the hell happed to you. 0,0

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This one sucks but :>

Debora [2.8K]3 years ago

4 0

Answer:

HERES THE BEST ONE

Step-by-step explanation:

You might be interested in

True or false????????????

Naddika [18.5K]

False for every rate there is only one unit rate. there is however more than 1 rates for one unit rate. for example 4/2 would have 2/1 as a unit rate but 2/1 can have 4/2 and 8/4 as rates and so on. hope this helps good luck!

8 0

3 years ago

The following 5 questions are based on this information: An economist claims that average weekly food expenditure of households

liq [111]

Answer:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b) 2.70

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

b. 1.85

$p_v =P(Z>1.85)=0.032$

b. 0.03

a. We can reject H(0) in favor of H(a)

Step-by-step explanation:

Data given and notation

$\bar X_{1}=164$ represent the mean for the sample 1

$\bar X_{2}=159$ represent the mean for the sample 2

$\sigma_{1}=12.5$ represent the population standard deviation for the sample 1

$s_{2}=9.25$ represent the population standard deviation for the sample B2

$n_{1}=35$ sample size selected 1

$n_{2}=30$ sample size selected 2

$\alpha=0.05$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the expenditure of households in City 1 is more than that of households in City 2, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{0}\leq 0$

Alternative hypothesis: $\mu_{1}-\mu_{2}>0$

We know the population deviations, so for this case is better apply a z test to compare means, and the statistic is given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-0}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Standard error

The standard error on this case is given by:

$SE=\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}$

Replacing the values that we have we got:

$SE=\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}=2.705$

b. 2.70

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{(164-159)-0}{\sqrt{\frac{12.5^2}{35}+\frac{9.25^2}{30}}}=1.850$

P-value

Since is a one side right tailed test the p value would be:

$p_v =P(Z>1.85)=0.032$

b. 0.03

Conclusion

If we compare the p value and the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis.

a. We can reject H(0) in favor of H(a)

4 0

3 years ago

3. Consider the functions f(x) = x2 + 10x – 5, g(x) = 8x + 1, and h(x) = 3x – 4. List the functions from least to greatest value

weeeeeb [17]

<u>x = 3</u>
f(x) = x²+ 10x - 5
f(3) = (3)² + 10(3) - 5
f(3) = 9 + 30 - 5
f(3) = 39 - 5
f(3) = 34

g(x) = 8x + 1
g(3) = 8(3) + 1
g(3) = 25

h(x) = 3x - 4
h(3) = 3(3) - 4
h(3) = 9 - 4
h(3) = 5

<u>x = 6
</u>f(x) = x² + 10x - 5
f(6) = (6)² + 10(6) - 5
f(6) = 36 + 60 - 5
f(6) = 96 - 5
f(6) = 91

g(x) = 8x + 1
g(6) = 8(6) + 1
g(6) = 48 + 1
g(6) = 49

h(x) = 3x - 4
h(6) = 3(6) - 4
h(6) = 18 - 4
h(6) = 14

I would explain to someone that you don't need to do any calculations to know the order of the functions when x is equal to 15 by knowing that f(x) is equal to 370, g(x) is equal to 121, and h(x) is equal to 41 to know that it is easy finding the function of x without calculating the answer.

4 0

3 years ago

PLS HELP ME ASAP WITH NUMBER 9 THANK YOUU

s2008m [1.1K]

9a)
4x - 2 + 30 = 68
4x + 28 = 68
4x = 40
x = 10

9b)
y = 180 -68
y= 112

4 0

3 years ago

A manufacturer has been selling 1400 television sets a week at $450 each. A market survey indicates that for each $21 rebate off

GuDViN [60]

Correct question is;

A manufacturer has been selling 1400 television sets a week at $450 each. A market survey indicates that for each $21 rebate offered to a buyer, the number of sets sold will increase by 210 per week

A) Find the demand function (price p as a function of units sold x).

p(x)=______

(B) How large a rebate should the company offer the buyer in order to maximize its revenue?

$=_____

Answer:

A) p(x) = (-1/10)x + 590

B) Rebate = $170

Step-by-step explanation:

A) We are told that p(x) is the demand function and x is the number of TV sets sold per week.

Now, since for each $21 rebate offered, the number of sets sold increases by 210 per week, it means that the slope here of this demand function is; m = -21/210 = -1/10

Now, he has been selling 1400 TV sets a week at $450 each. This means; p(1400) = $450

Thus, the demand function will be;

p(x) - 450 = (-1/10)(x - 1400)

Expanding the RHS;

p(x) - 450 = (-1/10)x + 140

Add 450 to both sides to get;

p(x) = (-1/10)x + 140 + 450

p(x) = (-1/10)x + 590

B) Formula for revenue is;

R = price × quantity sold

Our demand function is p = (-1/10)x + 590

Making x the subject, we have;

x = 5900 - 10p

x is quantity sold.

Thus,

R = p(5900 - 10p)

R = 5900p - 10p²

Maximum price will occur at dR/dP = 0

Thus;

dR/dP = 5900 - 20p

At dR/dP = 0,we have;

20p = 5900

p = 5900/20

p = $280

Thus, rebate = 450 - 280 = $170

6 0

2 years ago

Gimme some good memes, the best get Brainliest!​

Gimme some good memes, the best get Brainliest!