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3 years ago

Calculate dy/ds if y = Ln 2(x^3 + 3x)

Mathematics

1 answer:

tensa zangetsu [6.8K]3 years ago

8 0

Y = Ln (2x^3 + 3x)
then deriving
dy/dx= (1/(2x^3 + 3x))*(6x^2 + 3)

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What’s is the answer

kvasek [131]

When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.

For example:

$(x^{2} )^{3} = x^6$

$(x^{3} )^5=x^{15}$

When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.

For example:

$(x^{2} )(x^{3})=x^{5}$

$(x^{1} )(x^{2})=x^{3}$

$(\frac{(x^{-3})(y^{2})}{(x^{4})(y^{6})} )^{3}=\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}$

You multiply 3 into each exponent in the numerator and the denominator

$\frac{(x^{-9})(y^{6})}{(x^{12})(y^{18})}= \frac{y^{6}}{(x^{9})(x^{12})(y^{18})}$

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

$\frac{y^{6}}{(x^{21})(y^{18})} = \frac{1}{(x^{21})(y^{12})}$

When you have something like this:

$\frac{x^{2}}{x^5}$

You subtract the exponents together, so:

$\frac{x^2}{x^5} = x^{2-5} = x^{-3} = \frac{1}{x^3}$

Your answer is the second option

3 0

3 years ago

Can you please help me which one has the same value as 1.303

olya-2409 [2.1K]

Answer:

the answer is B

Step-by-step explanation:

6 0

3 years ago

Multiply. 5 x 1 1/3 Answer with a mixed number in simplest form.

Crank

Answer:

6 2/3

Step-by-step explanation:

5/1 * 4/3 = 20/3

20/3 = 6 with a remained of 2

4 0

3 years ago

Read 2 more answers

70 POINTS!

Sunny_sXe [5.5K]

Notation

The inverse of the function f is denoted by f -1 (if your browser doesn't support superscripts, that is looks like f with an exponent of -1) and is pronounced "f inverse". Although the inverse of a function looks like you're raising the function to the -1 power, it isn't. The inverse of a function does not mean the reciprocal of a function.

Inverses

A function normally tells you what y is if you know what x is. The inverse of a function will tell you what x had to be to get that value of y.

A function f -1 is the inverse of f if

for every x in the domain of f, f -1[f(x)] = x, andfor every x in the domain of f -1, f[f -1(x)] = x

The domain of f is the range of f -1 and the range of f is the domain of f -1.

Graph of the Inverse Function

The inverse of a function differs from the function in that all the x-coordinates and y-coordinates have been switched. That is, if (4,6) is a point on the graph of the function, then (6,4) is a point on the graph of the inverse function.

Points on the identity function (y=x) will remain on the identity function when switched. All other points will have their coordinates switched and move locations.

The graph of a function and its inverse are mirror images of each other. They are reflected about the identity function y=x.

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3 years ago

Who else going back to school on campus?

JulsSmile [24]

Heck naw Fawk that -3-!!!!!

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3 years ago