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julsineya [31]
3 years ago
5

Find the sum. 13(9−6m)+14(12m−8)

Mathematics
2 answers:
FinnZ [79.3K]3 years ago
7 0
To do this problem, we must first distribute the 13 and 14 into the parenthesis.

<span>13(9−6m)+14(12m−8)

117 - 78m + 168m - 112

To combine like terms, we can add/subtract terms that have an "m" together and then we can add/subtract terms that do not have "m" together.

117 - 112 = 5
and 
168m - 78m = 90m

So our final sum is 5 + 90m</span>
Grace [21]3 years ago
6 0
13(9-6m) + 14(12m-8)
117 - 78m + 168m - 112
(117 - 112) + (168m - 78m)
5 + 90m
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Four different roads from Town A to Town B, and three different roads run from Town B to Town C. Two roads also run from Town A
LekaFEV [45]

Answer:

196

Step-by-step explanation:

To solve this, I broke it down into two parts.

A. Number of routes going to Town C

4 x 3 + 2 = 14

B. Number of routes going back to Town A

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From here, it is easy to see what to do. Since there are 14 routes going to Town C and 14 routes going back, the answer is 14 x 14 = 196.

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3 years ago
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Furkat [3]

Answer:

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Solve for W <br> 4w^2+9w= -2
7nadin3 [17]

Answer:

w_1=-\frac{1}{4},w_2=-2}

Step-by-step explanation:

4w^2+9w=-2

4w^2+9w+2=0

w^2+9w+8=0

(w+1)(w+8)=0

(4w+1)(w+2)=0

w_1=-\frac{1}{4},w_2=-2}

3 0
2 years ago
The length of the hypotenuse of a 30-60 -90 triangle is 14 units. what is the length of the short leg
kifflom [539]

Recall that the short leg is the side opposite the 30 degrees angle. And the ratio of the short leg to the hypotenuse is 1:2.

Let the length of the short leg be x, then,

\cfrac{x}{14}=\cfrac{1}{2}\\ \\\Rightarrow2x=14\\ \\\Rightarrow x=\cfrac{14}{2}=7

6 0
3 years ago
11) Endpoint: (0,4), midpoint (-10, -3)<br> Find the endpoint?
earnstyle [38]

Answer:

(-20,-10)

Step-by-step explanation:

( - 10 \:  \:  - 3) = ( \frac{0 + x}{2}  \:  \:  \frac{4 + y}{2} )

Solve for.x coordinate

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solve for y coordinate

- 3 =  \frac{4 + y}{2}  \\  - 6 = 4 + y \\  - 10 = y

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